Answer:
It won't let me see the picture
Step-by-step explanation:
This is very simply since QPT is similar to QRS then we can set this as QP/QR=PT/RS=QT/QS now solve for x when putting in the values of each line. for example QP is is 20 and QR is x this means our first fraction is 20/x, now our second one is 12/8 sicne Pt is 12 and Rs 8, and our last one is 20/x. now we have 20/x=12/8=20/x lets just say we have 12/8=20/x first we have to find a common denominator in this case it can be 8x so multiply your numerator times the number you used to get 8x in the denominator, once you do it you will get 12x/8x=160/8x, now we can cancel our denominator sicne it is the smae thing and be left with 12x=160, now divide both sides by 12 to get x-=160/12, now simplify lets divideit by 4 first and get x=40/3 can that be simplified any more?? I dont think so so your final answer should be x=40/3
Hope this helps
12 ×12 =144 squares. an array is found by multiplying length units by width units. Much like finding the area
If you eliminate obvious wrong answers you increase your chances of getting the question correct.
Notice the inequality signs are both "equal to" which means a solid boundary line. This means choice B and D can not be correct.
You can test a point that is exclusively in the shaded region of each graph.
x + 2y ≤ 4
-x -x solve for y by moving x term
2y ≤ -x + 4
÷2 ÷2 divide both sides of the inequality by 2
y ≤ -1/2x + 2 ← plot 2 on y-axis then move down 1 and right 2 put 2nd point
shade below the solid line
3x - y ≥ 2 when solved for y → y ≤ 3x - 2 (the inequality sign switched because in the process of solving for y I had to divide by a negative number)
plot -2 on the y-axis then move up 3 and to the right 1 put 2nd point
shade below the line
the answer is choice A only graph where they have shaded below both lines...use the y-intercept as a guide for shading above or below the line... shading where numbers are greater than the y-intercept is shading above the line and shading where numbers are less then the y-intercept is shading below the line
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Step-by-step explanation:
since = 64