Answer:
An LS button
Explanation:
It appears on the (structure line 3)on the structure line, place your cursor in the <u>whi</u><u>te</u> field to the right of the E button (Recall that the E button represent the entry test).
Answer:
The answer for the following question is given as:
public static Temperature create(Sensor ob)
{
return new Temperature(ob.getReading());
}
Explanation:
In this we have create a static method of Temperature class which accept a 'Sensor' object and return the new 'Temperature' object that calls the 'getReading()' function This function returns the sensor's current reading.
Lowercase a is decimal 97 ; upper case is decimal 65
It's easier to think of them in octal, however: a = octal 141, and A is octal 101
octal to binary is easy, each digit is three bits.
141 = 001 100 001
101 = 001 000 001
So, how many bits are changed above?
It depends because if you put a stamp on the envelope. But I think that it will still get to the destination. I think that it will either get sent to the destination or not. But you never know what is going to happen.
Answer:
def prime_generator(s, e):
for number in range(s, e+1):
if number > 1:
for i in range(2, number):
if (number % i) == 0:
break
else:
print(number)
prime_generator(6,17)
Explanation:
I believe you want to ask the prime numbers between s and e.
- Initialize a for loop that iterates from s to e
- Check if the number is greater than 1. If it is, go inside another for loop that iterates from 2 to that number. If the module of that number to any number in range (from 2 to that number) is equal to 0, this means the number is not a prime number. If the module is not equal to zero, then it is a prime number. Print the number
