Answer:
The water cycle in a forest produces sufficient enough rainfall to sustain the rich plant and animal life in it. In a dessert, the water cycle provides just enough water for the animals and plants that reside in it, but not near enough for the life that is in a rain forest.
answer: white fur works as a camouflage against the white snow, allowing polar bears an advantage when hunting for food and hiding from predators
Answer:
It is a triglyceride
Explanation:
A triglyceride is a molecule that contains a glycerol group and three fatty acids linked by an ester linkage. A fatty acid is a molecule formed by a long linear hydrocarbon chain, of different length or number of carbon atoms, at the end of which is a carboxyl group. These chains can be saturated (with hydrogen) or when there are double bonds in the chain this reduces the available places of hydrogen that's why it's called unsaturated.
In the image you can see on the right the glycerol group. And the three fatty acids extending to the left. The top one is an example of a saturated fatty acid, and the two below unsaturated.
Triglycerides are generally solid at room temperature and are therefore called fats. For example, the fat that constitutes us is mostly formed by triglycerides.
Answer:
0.0159m
Explanation:
9 M
Explanation:
Lead(II) chloride,
PbCl
2
, is an insoluble ionic compound, which means that it does not dissociate completely in lead(II) cations and chloride anions when placed in aqueous solution.
Instead of dissociating completely, an equilibrium rection governed by the solubility product constant,
K
sp
, will be established between the solid lead(II) chloride and the dissolved ions.
PbCl
2(s]
⇌
Pb
2
+
(aq]
+
2
Cl
−
(aq]
Now, the molar solubility of the compound,
s
, represents the number of moles of lead(II) chloride that will dissolve in aqueous solution at a particular temperature.
Notice that every mole of lead(II) chloride will produce
1
mole of lead(II) cations and
2
moles of chloride anions. Use an ICE table to find the molar solubility of the solid
PbCl
2(s]
⇌
Pb
2
+
(aq]
+
2
Cl
−
(aq]
I
−
0
0
C
x
−
(+s)
(
+
2
s
)
E
x
−
s
2
s
By definition, the solubility product constant will be equal to
K
sp
=
[
Pb
2
+
]
⋅
[
Cl
−
]
2
K
sp
=
s
⋅
(
2
s
)
2
=
s
3
This means that the molar solubility of lead(II) chloride will be
4
s
3
=
1.6
⋅
10
−
5
⇒
s
= √
1.6
4
⋅
10
−
5 =
0.0159 M
Answer:
330.75 cm^3
Explanation:
d=m/v
10.5g/1 cm^3=31.5g/x cm^3
solve for x
round to the sig figs you have to.