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blagie [28]
4 years ago
13

When an object such a a stone is dropped into water, it disturbs the surface of the water. Waves form at the surface of the wate

r and travel outward from the point of the disturbance.
The diagram below is based on a single frame from a video of the waves that formed when a stone was dropped into water.


If a student were to measure the distance labeled as "Z," she would know the value of the _______ of the wave.
A.
wavelength
B.
amplitude
C.
radius
D.
frequency
Chemistry
2 answers:
Anna35 [415]4 years ago
8 0
A one way trip going 60mph took 30 minutes longer that the first trip going 70 mph. How far was the trip
vladimir1956 [14]4 years ago
3 0
B...................................
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Suppose that, from measurements in a microscope, you determine that a certain layer of graphene covers an area of 1.50μm2. Conve
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.0000015 meters squared. just got to move the decimal


3 0
3 years ago
What is the atomic mass of X ? Formula of the compound is XO3? Also identify the element X ? The molecular mass of XO3 is 80? (
djyliett [7]

Answer:

Explanation:

XO3

X + 3x16 = 80

x= 32  atomic mass for sulfur

SO3

6 0
3 years ago
A 112 gram sample of an unknown metal was heated from 0.0C to 20.0C. The sample absorbed 1004 J of energy. What was the specific
worty [1.4K]

Answer:

The specific heat of the sample unknown metal is approximately 0.45 J/g °C.

General Formulas and Concepts:
<u>Thermodynamics</u>

Specific Heat Formula: \displaystyle q = mc \triangle T

  • <em>m</em> is mass (g)
  • <em>c</em> is specific heat capacity (J/g °C)
  • Δ<em>T</em> is the change in temperature

Explanation:

<u>Step 1: Define</u>

<em>Identify variables.</em>

<em>m</em> = 112 g

Δ<em>T</em> = 20.0 °C

<em>q</em> = 1004 J

<u>Step 2: Solve for </u><u><em>c</em></u>

  1. Substitute in variables [Specific Heat Formula]:                                        \displaystyle 1004 \ \text{J} = (112 \ \text{g})(c)(20.0 \ ^{\circ} \text{C})
  2. Simplify:                                                                                                        \displaystyle 1004 \ \text{J} = (2240 \ \text{g} \ ^\circ \text{C})c
  3. Isolate <em>c</em>:                                                                                                        \displaystyle c = 0.448214 \ \text{J} / \text{g} \ ^\circ \text{C}
  4. Round [Sig Figs]:                                                                                          \displaystyle c \approx 0.45 \ \text{J} / \text{g} \ ^\circ \text{C}

∴ specific heat capacity <em>c</em> is equal to around 0.45 J/g °C.

---

Topic: AP Chemistry

Unit: Thermodynamics

5 0
3 years ago
Write the 1 g equivalents using the following prefixes: (a) mega−, (b) kilo−, (c) deci−, (d) centi−, (e) milli−, (f) micro−, (g)
dem82 [27]

<u>Explanation:</u>

Unit is defined as the quantity that is used as a standard for measurement.

S.I. unit of mass of kilograms. Other units in which mass of a substance can be measured are grams, milligrams, etc...

All these units are inter convertible.

  • <u>For a:</u> Mega-

The conversion factor used is:

1g=10^{-6}Mg

  • <u>For b:</u> kilo-

The conversion factor used is:

1g=10^{-3}kg

  • <u>For c:</u> deci-

The conversion factor used is:

1g=10dg

  • <u>For d:</u> centi-

The conversion factor used is:

1g=10^{3}cg

  • <u>For e:</u> milli-

The conversion factor used is:

1g=10^3mg

  • <u>For f:</u> micro-

The conversion factor used is:

1g=10^6\mu g

  • <u>For g:</u> nano-

The conversion factor used is:

1g=10^9ng

  • <u>For h:</u> pico-

The conversion factor used is:

1g=10^{12}pg

8 0
3 years ago
А<br> Newton's Third Law of Motion<br> states:<br> Edit<br> Move with text
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Newtown third law of motion says : when two objects interact , the forces they exert on each other are equal and opposite .
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