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blagie [28]
4 years ago
13

When an object such a a stone is dropped into water, it disturbs the surface of the water. Waves form at the surface of the wate

r and travel outward from the point of the disturbance.
The diagram below is based on a single frame from a video of the waves that formed when a stone was dropped into water.


If a student were to measure the distance labeled as "Z," she would know the value of the _______ of the wave.
A.
wavelength
B.
amplitude
C.
radius
D.
frequency
Chemistry
2 answers:
Anna35 [415]4 years ago
8 0
A one way trip going 60mph took 30 minutes longer that the first trip going 70 mph. How far was the trip
vladimir1956 [14]4 years ago
3 0
B...................................
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Round 0.0011675cg to four significant figures
atroni [7]

Answer:

answer is 0.001168 is correct

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3 years ago
You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8
Lubov Fominskaja [6]

Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is pK_a  =7.82

Explanation:

From the question we are told

    The volume of base is  V_B = 26.mL = 0.0260L

     The pH of solution is  pH =  7.82

      The concentration of the acid is C_A = 0.1M

From the pH we can see that the titration is between a strong base and a weak acid

 Let assume that the the volume of acid is  V_A = 18mL= 0.018L

Generally the concentration of base

                    C_B = \frac{C_AV_A}{C_B}

Substituting value  

                     C_B = \frac{0.1 * 0.01800}{0.0260}

                    C_B= 0.0692M

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

           HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}

Now before the reaction the number of mole of base is  

            No \ of \ moles[N_B]  =  C_B * V_B

Substituting value  

                    N_B = 0.01300 * 0.0692

                         = 0.0009 \ moles    

                                 

Now before the reaction the number of mole of acid is  

            No \ of \ moles  =  C_B * V_B

Substituting value  

                    N_A = 0.01800 *0.1

                         = 0.001800 \ moles

Now after the reaction the number of moles of  base is  zero  i.e has been used up

    this mathematically represented as

                         N_B ' = N_B - N_B = 0

    The  number of moles of acid is  

             N_A ' = N_A  - N_B

                   = 0.0009\ moles

The pH of this reaction can be mathematically represented as

                 pH  = pK_a + log \frac{[base]}{[acid]}

Substituting values

                  7.82 = pK_a +log \frac{0.0009}{0.0009}

                  pK_a  =7.82        

                     

             

                                 

       

           

                     

8 0
3 years ago
Which of the following showing the Law of Conservation of Mass?
Stells [14]
The only one I know for sure is Mass is always conserved In a Chemical reaction.
7 0
4 years ago
Read 2 more answers
O que é transferência de Calor?
irinina [24]

Answer:

I speak English can someone translate

Explanation:

7 0
3 years ago
Calculate the tempature of a 0.50 mol sample of a gas at a pressure of 0.987 atm and a volume of 12 L
dalvyx [7]

Answer:

The temperature is 288, 88K

Explanation:

We use the formula PV= nRT:

T= PV/nR

T= 0,987 atm x12 L/0,50 mol x 0,082 l atm/K mol

<em>T=288,88K</em>

6 0
3 years ago
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