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3 years ago

Which kind of molecule does the diagram represent?

Chemistry

1 answer:

inna [77]3 years ago

4 0

Answer:

It is a triglyceride

Explanation:

A triglyceride is a molecule that contains a glycerol group and three fatty acids linked by an ester linkage. A fatty acid is a molecule formed by a long linear hydrocarbon chain, of different length or number of carbon atoms, at the end of which is a carboxyl group. These chains can be saturated (with hydrogen) or when there are double bonds in the chain this reduces the available places of hydrogen that's why it's called unsaturated.

In the image you can see on the right the glycerol group. And the three fatty acids extending to the left. The top one is an example of a saturated fatty acid, and the two below unsaturated.

Triglycerides are generally solid at room temperature and are therefore called fats. For example, the fat that constitutes us is mostly formed by triglycerides.

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What is the charge of Cl3 in PCl3

irinina [24]

Are subatomic particles that are manifested by forces of attraction and repulsion between them through electromagnetisms

-good luck

5 0

3 years ago

A gas exerts a pressure of 2.5 ATM at a temperature

tino4ka555 [31]

(P1/T1)=(P2/T2)
(1atml/273K)=(2.5atm/x)
2.5/(1/273)=682.5K

5 0

3 years ago

a) What is the common-ion effect?b) Given an example of a salt that can decrease the ionization of HNO2 in solution. List all of

slega [8]

Answer:

Common ion effect refers to the decrease in the solubility of a substance in a solution with which it shares a common ion.

NaNO2

Explanation:

In order to understand exactly what common ion effect is, let us consider a simple unambiguous example. Assuming I have a solution of an ionic substance that contains a cation A and an anion B, this ionic substance has chemical formula AB. Secondly, I have another ionic distance with cation C and anion B, its chemical formula is CB. Both CB and AB are soluble in water to a certain degree as shown by their respective KSp.

If I dissolve AB in water and form a solution, subsequently, I add solid CB to this solution, the solubility of CB in this solution is found to be lees than the solubility of CB in pure water because of the ion B^- which is common to both substances in solution. We refer to the phenomenon described above as common ion effect.

Common ion effect refers to the decrease in the solubility of a substance in a solution with which it shares a common ion.

If I try to dissolve NaNO2 in a solution of HNO2, the solubility of NaNO2 in the HNO2 solution will be less than its solubility in pure water due to common ion effect. Also, the extent of ionization of HNO2 in a system that already contains NaNO2 will be decreased compared to its extent ionization in pure water. This system described here will contain HNO2, water and NaNO2

3 0

3 years ago

An herbicide contains only C, H, Cl, and N. The complete combustion of a 200.0 mg sample of the herbicide in excess oxygen produ

MAVERICK [17]

Answer:

%C = 56,1%

%H = 5,5%

%Cl = 27,6%

%N = 10,8%

Explanation:

The moles of CO₂ are the same than moles of C in the herbicide.

Moles of H₂O are ¹/₂ of moles of H in the herbicide.

Moles of CO₂ are obtained using:

n = PV/RT

Where, in STP: P is 1 atm; V is 0,2092L; R is 0,082atmL/molK; T is 273 K

moles of CO₂ are: 9,345x10⁻³ mol≡ mol of C×12,01g/mol = <em>0,1122 g of C ≡ 112,2mg of C</em>

In the same way, moles of H₂O are 5,450x10⁻³mol×2 =0,1090 mol of H×1,01g/mol = <em>0,0110 g of H ≡ 11,0mg of H</em>

As you have 55,14 mg of Cl, the mg of N are:

200,0mg - 112,2 mg of C - 11,0 mg of H - 55,14 mg of Cl = 21,66 mg of N

Thus, precent composition of the herbicide is:

%C = $\frac{112,2 mgC}{200,0mg}$ ×100 = 56,1%C

%H = $\frac{11,0 mgH}{200,0mg}$ ×100 = 5,5%H

%Cl = $\frac{55,14 mgCl}{200,0mg}$ ×100 = 27,6%Cl

%N = $\frac{21,66 mgN}{200,0mg}$ ×100 = 10,8%N

I hope it helps!

3 0

3 years ago

Which element would lose electrons during ionic bonding choose all that apply

yawa3891 [41]

Answer:

All of them!

Explanation:

Since Mg, Li, Ca, and Cs are all in groups 1 and 2 of the periodic table, they are alkali/alkaline earth metals and will all lose electrons during ionic bonding.

7 0

3 years ago