Complete Question
The complete question is shown on the first and second uploaded image
Answer:
The minimum mass of 
correct option is E
Explanation:
Free body diagram of the set up in the question is shown on the third uploaded image
The mass of board is 
The length of the board is 
The length extending over the edge is 
The second mass is 
Now to obtain 
we take moment about the edge of the platform
Substituting value
Angular width is 3 x 10^-3
Let D be the distance between source and screed d the distance between coherent source then for central diffraction maxima,
where λ is wavelength
Given:
λ = 450 nm = 450×10^−9m
d = 0.3x10^−3m, D = 1m
W = 2 x 450×10^−9/0.3x10^−3*1
To Find:
Angular width
Solution: The width of the central maxima is nothing but the difference between the positions of the first two minima. Hence we will use the expression for the position of minima and accordingly obtain the expression of the width of central maxima and secondary maxima
θ = W/D
θ = 2 x 450×10^−9/0.3x10^−3*1/1 = 3 x 10^-3
Hence, angular width is 3 x 10^-3
Learn more about Angular width here:
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<span>Angular speed = total degree / time
As = 360*(2.5) / 3.0 min (60)
As = 900 deg / 180 s
As =5 Degree / second</span>
Answer:
Friction opposes motion.
Explanation:
If there is relative motion, the frictional force is the kinetic force of friction.
Answer:
Explanation:
Given
Initial velocity of first billiard ball 
Initial velocity of second billiard ball 
After collision first ball comes to rest
suppose m is the mass of both the balls
Conserving momentum to get the speed of second ball after collision
Initial momentum 
Final momentum 
where 
and 
are the speed of first and second ball respectively
thus speed of second ball after collision is equal to speed of first ball before collision
