Answer: To solve for the net magnetic field of two circular loops of wire, each containing a single turn
B net= √[( NUI / 2R)^2 × ( NUI / 2R)^2]
Where B net = Net magnetic field
B net = √2 × (NUI/ 2R)
B net =[ √2 × 1 × ( 4 × 3.142 × 10^-7) × (1.8)] ÷ 2 × 0.034
B net = { 1.414 × (0.00000126) × (1.8)}÷ 0.068
B net = 4.72 × 10^-5 T
To solve this problem it is necessary to apply the concepts related to the orbital velocity of a satellite on earth.
This concept is expressed in the equation,
Where,
G = Universal Gravitational constant
Mass of the Earth
Therefore the ratio of the velocity from two satellites is,
The ratio between the two satellites is the same, then
Therefore the correct option is B.
Ptotal=Ptotal —> m1v1+m2v2=m1v1’+m2v2’ —> (1kg)(2m/s)+(1kg)(0m/s)=(1kg)(-1m/s)+(1kg)(v2’) —> v2’=3m/s
answer: v=3m/s
Joules is a unit for work which may decomposed into N.m. Work is a quantity which is a product of force (in this case, the woman's weight) and the distance she has traveled.
W = F x d ; d = W / F
Substituting the given,
d = (3.5 x 10^4 J) / (55 kg x 9.8 m/s²) = 64.94 m
Thus, the woman can climb up to 64.94 meters.
<u>Answer:</u>
The amount of the lighted side of the moon you can see is the same during "how much of the sunlit side of the moon faces Earth".
<u>Explanation:</u>
The Moon is in sequential rotation with Earth, and thus displays the Sun, the close side, always on the same side. Thanks to libration, Earth can display slightly greater than half (nearly 59 per cent) of the entire lunar surface.
The side of the Moon facing Earth is considered the near side, and the far side is called the reverse. The far side is often referred to as the "dark side" inaccurately but it is actually highlighted as often as the near side: once every 29.5 Earth days. During the New Moon the near side becomes blurred.
