The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.
![d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})](https://tex.z-dn.net/?f=d%27w%20%3D%20d_w%20%28%5Cfrac%7Bn_%7Bair%7D%7D%7Bn_w%7D%29%2Bd_g%20%28%5Cfrac%7Bn_%7Bair%7D%7D%7Bn_g%7D%29)
Where,
Depth of glass
Refraction index of water
Refraction index of glass
Refraction index of air
Depth of water
I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to
![d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})](https://tex.z-dn.net/?f=d%27w%20%3D%20d_w%20%28%5Cfrac%7Bn_%7Bair%7D%7D%7Bn_w%7D%29%2Bd_g%20%28%5Cfrac%7Bn_%7Bair%7D%7D%7Bn_g%7D%29)
![d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})](https://tex.z-dn.net/?f=d%27w%20%3D%20%281.7cm%29%20%28%5Cfrac%7B1%7D%7B1.33%7D%29%2B%284.2cm%29%28%5Cfrac%7B1%7D%7B1.52%7D%29)
![d'w = 4.041cm](https://tex.z-dn.net/?f=d%27w%20%3D%204.041cm)
Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm
Answer:
Buoyant force = 3.0 N
The object will not float.
Explanation:
Apparent weight of a body immersed in water is the actual weight of object minus buoyant force
Given in the question that;
Weight of object in air = 7.0 N
Apparent weight of object = 4.0 N
4.0 N = 7.0 N - Buoyant force
Buoyant force = 7.0 - 4.0 = 3.0 N
In this case, the buoyant force is less than weight of the object thus the object will sink.
The average electric current in the lightning will be 8 ×
A
<h3>
Why Lightning Conductors on top of a tower ?</h3>
The lightning conductors are long metal strips running from the spike end of a conductor on the top of a building to the earth. They are used to prevent buildings from destruction when struck by thunder or lightning.
Given that a lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms, to calculate the average electric current in the lightning, we will first consider the charge released.
one charge = 1.6 ×
C
Average current I = Q/t
Where
- Q = charge = 1.6 ×
C
- t = time = 2ms = 2 ×
s
Substitute all the parameters into the formula
I = 1.6 ×
C ÷ 2 × ![10^{-3}](https://tex.z-dn.net/?f=10%5E%7B-3%7D)
I = 8 ×
A
Therefore, the average electric current in the lightning will be 8 ×
A
Learn more about Lightning here: brainly.com/question/3183045
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Answer:c
Explanation:because when u push the oar back u go forward
Answer:
positive degree:
No other peak of the Himalayas is as high as Mount everest