Answer:
Explanation:
Given data
Average intensity of sunlight on one day I=700 W/m²
Power P=170 W
To find
Area A
Solution
As we know that:
<span>A physical change involves a change in physical properties. Examples of physical properties include melting, transition to a gas, change ofstrength, change of durability, changes to crystal form, textural change, shape, size, color, volume and density.b
A) physical properties</span>
A. Rain falling from the sky.
Work is equal to a force over a distance and is equal to the change in kinetic energy, so
<span>
- Fd=ΔKE
</span>
<span>−Fd=1/2m<span>v22</span>−1/2m<span>v21</span></span>
<span>d=(1/2m<span>v22</span>−1/2m<span>v21</span>)/−F
</span>
We know that Ffric=kFnatural and Fnatural=mg so:
<span>d=(1/2m<span>v22</span>−1/2m<span>v21</span>)/−(k∗mg)</span><span>d=(−1/2<span>v21</span>)/−(k∗g)
</span><span>d=(−1/2×(14.6m/s<span>)2</span>)/−(0.137×9.8m/s)
</span><span>
d = 78.9m</span>
Answer:
C. 0.25J
Explanation:
Energy stored in the magnetic field of the inductor is expressed as E = 1/2LI² where;
L is the inductance
I is the current flowing in the inductor
Given parameters
L = 20mH = 20×10^-3H
I = 5A
Required
Energy stored in the magnetic field.
E = 1/2 × 20×10^-3 × 5²
E = 1/2 × 20×10^-3 × 25
E = 10×10^-3 × 25
E = 0.01 × 25
E = 0.25Joules.
Hence the energy stored in the magnetic field of this inductor is 0.25Joules
