The mass of the cold water, given the data from the question is 500 g
<h3>Data obtained from the question</h3>
- Mass of warm water (Mᵥᵥ) = 200 g
- Temperature warm water (Tᵥᵥ) = 75 °C
- Temperature of cold water (T꜀) = 5 °C
- Equilibrium temperature (Tₑ) = 25 °C
- Specific heat capacity of the water = 4.184 J/gºC
- Mass of cold water (M꜀) =?
<h3>How to determine the mass of the cold water </h3>
Heat loss = Heat gain
MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – T꜀)
200 × 4.184 (75 – 25) = M꜀ × 4.184(25 – 5)
41840 = M꜀ × 83.68
Divide both side 83.68
M꜀ = 41840 / 83.68
M꜀ = 500 g
Learn more about heat transfer:
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Answer:
It corresponds to 1mm-10 mm range.
Explanation:
- Electromagnetic waves (such as the millimeter-wave radiation) travel at the speed of light, which is 3*10⁸ m/s in free space.
- As in any wave, there exists a fixed relationship between speed, frequency and wavelength, as follows:

- Replacing v= c=3*10⁸ m/s, and the extreme values of f (which are givens), in (1) and solving for λ, we can get the free-space wavelengths that correspond to the 30-300 GHz range, as follows:


Answer:
Explanation:
Let x ft be used to make square and 2-x ft be used to make equilateral triangle.
each side of square = x/4
area of square = ( x /4 )²
Each side of triangle
= (2-x) /3
Area of triangle = 1/2 (2-x)²/9 sin 60
= √3 / 36 x (2-x)²
Total area
A = ( x /4 )² +√3 / 36 (2-x)²
For maximum area
dA/dx = 0
1/16( 2x ) -√3 / 36 x2(2-x) = 0
x / 8 - √3(2-x)/ 18 = 0
x / 8 - √3/9 + √3/18 x = 0
x ( 1/8 + √3/18 ) = √3/9
x(.125 +.096 ) = .192
x = .868 ft
Answer:
5.42 m/s
Explanation:
At minimum speed, the tension in the bar will be 0 when the ball is at the top of the arc, so the only force is gravity pulling down.
Sum of forces towards the center of the circle:
∑F = ma
mg = m v²/r
v = √(gr)
v = √(9.8 m/s² × 3.00 m)
v = 5.42 m/s