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NISA [10]
3 years ago
6

The cable of a hoist has a cross-section of 80 mm 2 . The hoist is used to lift a crate weighing 500 kg. What is the stress in t

he cable? The free length of the cable is 3 m. How much will it extend if it is made of steel (modulus 200 GPa)? How much if it is made of polypropylene, PP (modulus 1.2 GPa)?
Physics
1 answer:
motikmotik3 years ago
4 0

Answer:

0.0009196875 m

0.15328125 m

Explanation:

Y = Young's modulus

Stress is given by

\sigma=\dfrac{mg}{A}\\\Rightarrow \sigma=\dfrac{500\times 9.81}{80\times 10^{-6}}\\\Rightarrow \sigma=61312500\ Pa

Change in length is given by

\Delta L=\dfrac{L\sigma}{Y}\\\Rightarrow \Delta L=\dfrac{3\times 61312500}{200\times 10^9}\\\Rightarrow \Delta L=0.0009196875\ m

The change in length of steel is 0.0009196875 m

\Delta L=\dfrac{L\sigma}{Y}\\\Rightarrow \Delta L=\dfrac{3\times 61312500}{1.2\times 10^9}\\\Rightarrow \Delta L=0.15328125\ m

The change in length of polypropylene is 0.15328125 m

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A 600-kg car traveling at 30.0 m/s is going around a curve having a radius of 120 m that is banked at an angle of 25.0°. The coe
andrey2020 [161]

Answer:

The magnitude of force is 1593.4N

Explanation:

The sum of the horizontal components of the friction and the normal force will be equal to the centripetal force on the car. This can be represented as

fcostheta + Nsintheta = mv^2/r

Where F = force of friction

Theta = angle of banking

N = normal force

m = mass of car

v = velocity of car

r = radius of curve

The car has no motion in the vertical direction so the sum of forces = 0

The vertical component of the normal force acts upwards whereas the weight of the car and the vertical component friction acts downwards.

Taking the upward direction to be positive,rewrite the equation above to get:

Ncos thetha = mg - fsintheta =0

Ncistheta = mg + fain theta

N = mg/cos theta + sintheta/ costheta

fcostheta +[mg/costheta + ftan theta] sin theta = mv^2/r

Substituting gives:

f = (1/(costheta + tanthetasintheta) + mgtantheta = mv^2/r - mgtantheta)

Substituting given values into the above equation

f = 1/(cos25 + tan 25 )(sin25)[ 600×30/120 - (600×9.81)tan

f = 1593.4N25

4 0
3 years ago
Read 2 more answers
A baton twirler is twirling her aluminum baton in a horizontal circle at a rate of 2.33 revolutions per second. A baton held hor
Nata [24]

Answer:

Explanation:

Given that;

horizontal circle at a rate of 2.33 revolutions per second

the magnetic field of the Earth is 0.500 gauss

the baton is 60.1 cm in length.

the magnetic field  is oriented at 14.42°

we wil get the area due to rotation of radius of baton is

\Delta A = \frac{1}{2} \Delta \theta R^2

The  formula for the induced emf is

E = \frac{\Delta  \phi}{\Delta  t}

\phi  = \texttt {magnetic flux}

E=\frac{\Delta (BA) }{\Delta  t}

=B\frac{\Delta  A}{\Delta  t}

B is the magnetic field strength

substitute

\texttt {substitute}\  \frac{1}{2} \Delta \theta R^2 \ \ for \Delta  A

E=B\frac{(\Delta  \theta R^3/2)}{\Delta  t} \\\\=\frac{1}{2} BR^2\omega

The magnetic field of the earth is oriented at 14.42

\omega =2.33\\\\L=60.1c,\\\\\theta=14.42\\\\B=0.5

we plug in the values in the equation above

so, the induce EMF will be

E=\frac{1}{2} \times (B\sin \theta)R^2\omega\\\\E=\frac{1}{2} \times (B\sin \theta)(\frac{L}{2} )\omega

=\frac{1}{2} \times0.5gauss\times\frac{0.0001T}{1gauss} \times\sin 14.42\times(\frac{60.1\times10^-^2m}{2} )^2(2.33rev/s)(\frac{2\pi rad}{1rev} )\\\\=2.5\times10^-^5\times0.2490\times0.0903\times14.63982\\\\=2.5\times10^-^5\times0.32917\\\\=8.229\times10^-^6V

6 0
3 years ago
Identical spheres are dropped from a height of 100 m above the surfaces of Planet X and Planet Y. The speed of the spheres as a
Anna007 [38]

Answer:B

Explanation:

8 0
2 years ago
If a machine is doing 500 J of work with 75 watts of power, how long did it take to complete its task?
kompoz [17]

Answer:

time = 6.67secs

Explanation:

power = workdone( energy) / time

therefore :

Time = workdone / power

time = 500 / 75

time = 6.67secs

3 0
3 years ago
9. a) What is the Doppler effect? b) How does it work? c) If 12 points
mart [117]

a) Doppler effect is an apparent change in the frequency of a wave due to the relative motion between the source and the observer

b) It is given by the equation f'=\frac{v\pm v_o}{v\pm v_s}f

c) The star is moving towards us

Explanation:

a)

The Doppler effect is a phenomenon that occurs whenever there is a source of a wave in relative motion to an observer. When such situation occurs, the apparent frequency of the sound as perceived by the observe is different from the proper frequency of the wave emitted by the source.

A typical example of this situation is when an ambulance is approaching you. The sound of the siren is perceived as having a higher pitch (higher frequency) as the ambulance moves towards you, and then is perceived as having a lower pitch (lower frequency) when the ambulance moves away from you.

The same phenomenon occurs not only with sound waves, but also with light waves and other types of waves.

b)

Mathematically, the Doppler effect can be summarized by the following equation:

f'=\frac{v\pm v_o}{v\pm v_s}f

where:

f is the proper frequency of the wave emitted by the source

f' is the apparent frequency, as perceived by the observer

v is the speed of the wave

v_o is the velocity of the observer, which is positive if the observer is moving towards the source and negative if the observer is moving away from the source

v_s is the velocity of the source, which is positive if the source is moving away from the observer and negative if the source is moving towards the observer

Applied to the example of the ambulance, we have that:

v_o = 0, assuming that the observer is at rest

- when the ambulance is moving towards the observer, v_s is negative, and therefore the fraction is larger than 1, therefore f'>f and the apparent frequency is higher than the real frequency

- when the ambulance is moving away from the observer, v_s is positive, and therefore the fraction is  smaller than 1, therefore f' and the apparent frequency is lower than the real frequency

c)

As we mentioned earlier, the Doppler effect also occurs with light waves. This is particularly relevant for stars or galaxies moving towards or away from us, since the light coming from these objects will have a frequency (and also a wavelength) "shifted" due to the Doppler effect.

In particular, we have two possible  cases:

- For a star moving away from us, the frequency of the light emitted by the star will appear lower than the real frequency --> this means that its wavelength will appear longer than the real wavelength (because wavelength is inversely proportional to the frequency), and this means that the light will appear shifted towards longer wavelengths (so, towards the red end of the visible spectrum)

- For a star moving away towards us, the frequency of the light emitted by the star will appear higher than the real frequency --> this means that its wavelength will appear shorter than the real wavelength, and this means that the light will appear shifted towards shorter wavelengths (so, towards the blue end of the visible spectrum)

Therefore, if a star looks bluer to us than it should, the star is moving towards us.

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

8 0
3 years ago
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