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3 years ago

A man has a mass of 110kg. What is his weight?

Physics

1 answer:

Stells [14]3 years ago

5 0

His weight depends on where he is, because

Weight = (mass) x (gravity in the place where the mass is) .

For example:

-- If this man is on Mars, his weight is (110 kg) x (3.7 m/s²) = 408 Newtons

-- If he is on the Moon, his weight is (110 kg) x (1.6 m/s²) = 176 Newtons

-- If he is on Earth, his weight is (110 kg) x (9.8 m/s²) = 1,078 Newtons

-- If he is in a spacecraft coasting from one to another, his weight is zero.

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Pedal Power A person in good physical condition can put out 95 W of useful power for several hours at a stretch, perhaps by peda

stiv31 [10]

Answer:

48 people would it take to run a 4.64 kW electric clothes dryer.

Explanation:

Given:

Pedal power A $W_{1} = 95$ W

Electric clothes dryer power $W_{2} = 4640$ W

For finding the number of person $n$ equals :

$n = \frac{W_{2} }{W_{1} }$

$n = \frac{4640}{95}$

$n = 48.84$

Therefore, 48 people would it take to run a 4.64 kW electric clothes dryer.

5 0

4 years ago

A car accelerates uniformly from rest to a speed of 7.6 m/s in 4.6 s. How far does the car travel in that time?

uysha [10]

Answer:

The car will travel a distance of 17.45 meters.

Explanation:

Given:

Initial velocity $(V_i)$ = 0

Final velocity $(V_f)$ = 7.6 m/s

Time taken = 4.6 s

Acceleration = (Final velocity - Initial Velocity )/time

$a=\frac{(V_f-Vi)}{t}= \frac{7.6-0}{4.6}=1.65\ ms^-2$

We have to calculate total distance traveled by the car.

Let the distance traveled be 'd'

Equation of motion:

$d=V_i(t)+\frac{at^2}{2}$

Plugging the values.

⇒ $d=V_i(t)+\frac{at^2}{2}$

⇒ $d=0+\frac{1.65*(4.6)^2}{2}$

⇒ $d=17.45\ m$

The car will travel a distance of 17.45 meters for the above case.

4 0

3 years ago

A 110 kg tackler moving at 2.5m/s meets head on (and holds on to) an 82 kg halfback moving at 5.0m/s. what will be their mutual

Leona [35]

Answer:

0.7 m/s

Explanation:

We can solve the problem by using conservation of momentum.

Before the collision, the momentum of the first tackler is:

$p_1 = m_1 v_1 =(110 kg)(2.5 m/s)=275 kg m/s$

while the momentum of the second tackler is

$p_2 = m_2 v_2 =(82 kg)(-5.0 m/s)=-410 kg m/s$

Note that we used a negative sign because the direction of the second tackler is opposite to that of the first tackler.

Therefore, the total momentum before the collision is

$p_i = p_1 +p_2 =275 kg m/s -410 kg m/s=-135 kg m/s$

Since the total momentum is conserved, this is also equal to the final total momentum :

$p_f = -135 kg m/s$

Which is also equal to

$p_f = (m_1 +m_2 )v_f$

since the two tacklers continue their motion together with final velocity vf. Re-arranging the previous equation, we can find the the new velocity of the two tacklers:

$v_f = \frac{p_f}{m_1 +m_2}=\frac{-135 kg m/s}{110 kg + 82 kg}=-0.7 m/s$

and the negative sign means the direction is the one of the second tackler.

3 0

3 years ago

Read 2 more answers

If the speed of the magnet is doubled, the induced voltage is ________ . twice as great four times as great half as great unchan

Rina8888 [55]

If the speed of the magnet is doubled, the induced voltage is twice as great

Faraday's law of induction states that whenever relative motion exists between a coil and magnetic field, a voltage will induce in the circuit and this voltage is proportional to the rate of change of the flux. The expression for the motional emf is as follows:

ε=Blv

Here, ε is the motional emf, B is the magnetic field, l is the length of the conductor, and v is the velocity at which the magnetic field changes.

The induced voltage by the moving magnet is directly proportional to the speed of the magnet. Therefore, an increase in the speed of the magnet will increase the induced voltage.

If the speed of the magnet is doubled, the induced voltage is twice as great

Find out more at: brainly.com/question/13369951

4 0

2 years ago

During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 6.82 s, how high does it rise? The accel

scoray [572]

The answer is 56.98 m

The dislocation (d) is:
d = v1 * t + 1/2 * a * t²
v1 - initial velocity
t - time
a - <span>acceleration of gravity

We know:
d = ?
v1 = ?
t = 6.82 s / 2 = 3.41 (it reaches the peak at half time)
a = - 9.8 m/s</span>²

Let's first calculate v1:
v2 = v1 + at
v2 - final velocity (v2 = 0 when it reaches peak)

0 = v1 + -9.8 * 3.41
0 = v1 - 33.418

v1 = 33.418 m/s

d = v1 * t + 1/2 * a * t²
d = 33.418 * 3.41 + 1/2 * -9.8 * 3.41²
d = 113.96 - 56.98
d = 56.98 m

8 0

4 years ago