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Alex787 [66]
3 years ago
8

A man has a mass of 110kg. What is his weight?

Physics
1 answer:
Stells [14]3 years ago
5 0

His weight depends on where he is, because

Weight = (mass) x (gravity in the place where the mass is) .

For example:

-- If this man is on Mars, his weight is (110 kg) x (3.7 m/s²) =  408 Newtons

-- If he is on the Moon, his weight is (110 kg) x (1.6 m/s²) =  176 Newtons

-- If he is on Earth, his weight is (110 kg) x (9.8 m/s²) =  1,078 Newtons

-- If he is in a spacecraft coasting from one to another, his weight is zero.

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A technician places a fluid substance, with a refractive index of 1.61, between two horizontal panes of flat glass (each of whic
Ahat [919]

Answer:

the minimum thickness (in nm)  t = 102.5 nm

Explanation:

t = thickness of the film

n = index of refraction = 1.61

m = order = 1

∝ = wavelength = 330 x 10-9 m

so we have the formula

2nt = m∝

2 (1.61) t = (1) (330 x 10-9)

then...

t = 1.025 x 10-7 m

converting...

t = 102.5 nm

5 0
3 years ago
Sebuah benda berjarak 8 cm di depan cermin cekung yang memiliki fokus 12 cm. perbesaran bayangan yang dihasilkan adalah??
Len [333]
1/s' = 1/f - 1/s
        = 1/12 - 1/8
        = 2/24 - 3/24
        = 2-3/24
        = - 1/24
s'= -24
M= |s'/s|
M = |24/8|
M = 3
4 0
3 years ago
A 1.0 kg ball at the end of a 2.0 m string swings in a vertical plane. At its lowest point the ball is moving with a speed of 10
Trava [24]

Answer:

a) 4.65m/s

b) 59.8 N , 1.01125 N

Explanation:

a)

m = mass of the ball = 1 kg

r = length of the string = 2.0 m

h = height gained by the ball as it moves from lowest to topmost position = 2r = 2 x 2 = 4 m

v = speed at the lowest position = 10 m/s

v' = speed at the topmost position = ?

Using conservation of energy

Kinetic energy at topmost position + Potential energy at topmost position = Kinetic energy at lowest position

(0.5) m v'² + m g h = (0.5) m v²

(0.5) v'² + g h = (0.5) v²

(0.5) v'² + (9.8 x 4) = (0.5) (10)²

v' = 4.65m/s

b)

T' = Tension force in the string when the ball is at topmost position

T = Tension force in the string when the ball is at lowest position

At the topmost position:

force equation is given as

mg + T' = \frac{m v'^{2}}{r}

(1)(9.8) + T' = \frac{(1) (4.65)^{2}}{2}

T' = 1.01125 N

At the lowest position:

force equation is given as

T - mg = \frac{m v^{2}}{r}

T - (1) (9.8) = \frac{(1) (10)^{2}}{2}

T = 59.8 N

8 0
4 years ago
ANSWER FOR BRAINILEST
umka2103 [35]
C) 60 mph
I hope this helps =)
6 0
3 years ago
What is the mass of 5 m3 of cement of 3000 kg/m-3​
Scilla [17]

Answer:

It is 15000 Kgs.

4 0
3 years ago
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