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3 years ago

11

What's the answer ?

rt{245 + 44} " alt=" \sqrt{245 + 44} " align="absmiddle" class="latex-formula">

2 answers:

-Dominant- [34]3 years ago

8 0

$\huge\mathfrak\pink{Answer...}$

+,- 17

$\huge\mathfrak\purple{hope \: it \: helps..}$

Vikki [24]3 years ago

6 0

hope it is helpful to you

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Mei Mei invested $1700 in an account that pays 3% interest compounded annually.

algol [13]

Answer:

$2728

Step-by-step explanation:

Use compound interest formula:

$A = P(1 + \frac{r}{n})^{nt}$

P = 1700, r = 0.03, n = 1, t = 16

Plug in numbers:

$A = 1700(1 + \frac{0.03}{1})^{(1)(16)}$

Simplify:

$A = 1700(1.3)^{16$

Use calculator:

$A = 2728$

4 0

2 years ago

Rachel made $176 for 11 hours of work.

elena55 [62]

Answer:

8 hours

Step-by-step explanation:

11 hours = $176

⇒ 1 hour = $176 ÷ 11 = $16

To determine how many hours she would have to work to make $128, divide $128 by $16:

⇒ number of hours = $128 ÷ $16

= 8 hours

6 0

2 years ago

Read 2 more answers

Csc (2sin^-1(-12/13))<br> that is 2 times inverse sin of -12/13

german

Answer: $-\frac{169}{120}$

I'm assuming you mean this:

$cosec(2sin^{-1}(\frac{-12}{13}))$

Recall what the cosecant function represents. It is the reciprocal of a sine function, and is often written in this form:

$\frac{1}{sinx}$

So, using the sine relationship:

$cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2sin^{-1}(\frac{-12}{13}))}$

Let $u = sin^{-1}(\frac{-12}{13})$
$cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2u)}$
$= \frac{1}{2sinu \cdot cosu}$
$= \frac{1}{2sin(sin^{-1}(\frac{-12}{13})) \cdot cos(sin^{-1}(\frac{-12}{13}))}$
$= \frac{1}{\frac{-24}{13} \cdot \sqrt{1 - (\frac{-12}{13})^{2}}}$
$= \frac{1}{\frac{-24}{13}} \cdot \frac{1}{\sqrt{1 - \frac{144}{169}}}$
$= -\frac{13}{24} \cdot \frac{1}{\sqrt{\frac{25}{169}}}$
$= -\frac{13}{24} \cdot \frac{1}{\frac{5}{13}}$
$= -\frac{13}{24} \cdot \frac{13}{5}$
$= -\frac{169}{120}$

3 0

3 years ago

Four times the difference of a number 5 is 24

Dmitry [639]

4(x-5)=24 would be your answer.

3 0

3 years ago

Read 2 more answers

Composing functions is a way to "link" them together.<br> A. True<br><br> B. False

Sati [7]

This statement is true.

8 0

3 years ago