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4 years ago

Will mark brainliest if correct

Mathematics

1 answer:

lord [1]4 years ago

8 0

Answer:

$mean = \frac{9 + 4 + 4 + 1 + 0 + 6 + 4}{7} = \frac{28}{7} = 4$

$mean \: deviation = \frac{ |9 - 4| + |4 - 4| + |4 - 4| + |1 - 4| + |0 - 4| + |6 - 4| + |4 - 4| }{7} = \frac{5 + 0 + 0 + 3 + 4 + 2 + 0}{7} = \frac{14}{2} = 7$

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6 divided by negative 3 minus 15 minus 7 divided by negative 2

pickupchik [31]

To answer this question you would need to use PEMDAS. Since you don't have any parentheses or exponents, you would start by doing all division from left to right. After that you would do the subtraction from left to right. Your final answer should be -13.5

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mylen [45]

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What Is The Value Of n So That The Expression

vlabodo [156]

Given is the expression, x² + 12x + n

It says to find value of 'n' that converts it into a Perfect Square Trinomial.

A perfect square trinomial is a quadratic expression which has a single root with multiplicity 2. i.e. it is of the form :- x² + 2bx + b² = (x + b)²

On comparing it with the given expression, we get :-

So 2b = 12 and n = b²

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and so b² = 6² = 36.

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Hence, x² + 12x + 36 = (x + 6)² i.e. n = 36 is the final answer.

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3 years ago

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What kind of sequence is this? 35, 29, 23, 17, ...

vlada-n [284]

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3 years ago

In a experiment on relaxation techniques, subject's brain signals were measured before and after the relaxation exercises with t

yKpoI14uk [10]

Answer:

There is no sufficient evidence to suggest that the relaxation exercise slowed the brain waves

Step-by-step explanation:

Given that in a experiment on relaxation techniques, subject's brain signals were measured before and after the relaxation exercises with the following results:

The population is normally distributed

This is a paired t test since sample size is very small and same population under two different conditions studied.

$H_0: \bar x-\bar y =0\\H_a: \bar x >\bar y$

(Right tailed test)

Alpha = 5%

x y Diff

32 26 6

38 36 2

66 59 7

49 52 -3

29 24 5

Mean 3.4

Std dev 4.037325848

Mean difference = $3.40$

n =5

Std deviation for difference = $4.037326$

Test statistic t = mean difference / std dev for difference

= $1.883$

p value =0.132

Since p >0.05 we accept null hypothesis.

There is no sufficient evidence to suggest that the relaxation exercise slowed the brain waves

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4 years ago