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Natasha_Volkova [10]
2 years ago
14

Which of the following describes the domain of y= tan x, where n is any

Mathematics
1 answer:
GrogVix [38]2 years ago
5 0

Answer:

A. x≠npi is right B. x≠pi/2+npi,C. x≠npi/2,D. X≠27npi are wrong

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3 elevenths divided by 3 elevenths
WARRIOR [948]

Answer:

1

Step-by-step explanation:

3/11 *3/11

2nd 3/11 flips over. Then multiply. Then u get 33/33 which equals 1

8 0
2 years ago
Help please!!! | DON'T GUESS, please show work
Aleksandr-060686 [28]
For one of the triangular sides, 2.6 x 4 = 10.4 divided by 2 = 5.2
Other triangle; 2.6 x 3 = 7.8 /2 = 3.9
Rectangular side in front; 6.5 x 3 = 19.5
Back; 6.5 x 4 = 26
Base; 6.5 x 2.6 = 16.9
Answer: For the surface area it is 74.6 (SUPER SORRY IF THIS ISNT RIGHT OMG)
5 0
3 years ago
F(x)=2x+3 find x=9 explain how you got the answer please help me I need the answer today
hram777 [196]
You would fill in 9 for x so your equation would be 2(9)+3 and you would then get 21. Therefore the answer is f(x)=21
6 0
3 years ago
In which figure is DE BC
stepan [7]

Answer:

Given: DB = 7.2 cm, AE = 1.8 cm and EC = 5.4 cm and DE || BC.

DB

AD

=

AC

AE

[by basic proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same.

7.2

AD

=

5.4

1.8

AD=

5.4

7.2×1.8

AD=

10

24

⟹AD=2.4cm

4 0
3 years ago
In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha
siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95,  P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0
3 years ago
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