0.118 m is the distance between the two protons.
Mass of proton = 1.6726 × 10⁻²⁷ kg
Weight of proton= 1.6726 × 10⁻²⁷ x 9.81 N
= 1.6408 × 10⁻²⁶ N
Charge of proton = 1.602 × 10⁻²⁹ C
The force between two protons = kq²/r² where, K is a proportionality
constant, q is a charge of proton and
r is the distance between two protons.
= 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²
To calculate distance :
Weight of proton= Force between protons
⇒ 1.6408 × 10⁻²⁶ N = 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²
⇒ r = 0.118m
Therefore, 0.118 m is the distance between the two protons.
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Answer:
d = 90 ft
Explanation:
As we know that after each bounce it reaches to 4/5 times of initial height
so we can say

so the distance covered is given as

here we know that
h = 10 feet



Given:
ρ = 1.18 kg/m³, density of air
v = 8 m/s, flow velocity
Q = 9 m³/s, volumetric flow rate
The minimum power required (at 100% efficiency) is

The actual power will be higher because 100% efficiency is not possible.
Answer: 339.8 W (nearest tenth)
C. The light bulb will be off
This is due to the reason that the wire doesn’t go back to the battery :)