Answer:
Δω = -6.00 rad/s
α = -2.61 m/s²
Explanation:
Step 1: Data given
A bicycle tire is spinning counterclockwise at 3.00 rad/s
Δt = 2.30 s
In theopposite (clockwise) direction, also at 3.00 rad/s
Step 2: Calculate the change in the tire's angular velocity Δω
Δω = ωf - ωi
ωf = - 3.00 rad/s
ωi = 3.00 rad/s
Δω = ωf - ωi = -3.00 - 3.00 = -6.00 rad/s
Step 3: Calculate the tire's average angular acceleration α
α = Δω / ΔT
α = -6.00 rad/s /2.30s
α = -2.61 m/s²
A negative angular acceleration means a decreasing angular velocity
KE = 1/2 mv^2
KE = 1/2 (700)(80)^2
KE = 2240000 J
A contour line represents a certain vertical height above the contour line shown. They are means of representing 3D hills and moutains on 2D paper.
