<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
Answer:
put a dot on -5 on the y axis
Step-by-step explanation:
Answer:
= 2 4/15 km
Step-by-step explanation:
Speed = 3 2/5 km/hour
The units are not the same. The speeds is in hours and the time is in minutes
Lets convert minutes to hours. 60 minutes = 1 hour
40 minutes * 1 hour/ 60 minutes = 40/60 hours = 2/3 hour
Distance = speed * time
= 3 2/5 * 2/3
Change the mixed number to an improper fraction
3 2/5 = (5*3+2)/5 = 17/5
= 17/5 * 2/3
= 34/ 15 km
Change this back to a mixed number
15 goes into 34 2 times (15*2 = 30) with 4 left over
= 2 4/15 km
Answer:
A
Step-by-step explanation:
If the image reflects across the x axis, the x stays the same but y flips:
(-7, 6) across x axis is (-7, -6) so it is A
