Plz help.....................

Answer please I only need 3a and 3b ignore the rest

babunello [35]

Answer:

The chocolates are heavier than the weight the weight stated on the label. And the chocolates are 0.0042 pounds heavier.

Step-by-step explanation:

Given:

Weight of the chocolates in the bag is labeled = 0.384 pounds.

The actual weight of the chocolates = 0.3798 pounds.

Now, to find is the chocolates are heavier or lighter than the weight stated on the label and how much it is heavier or lighter.

So, we see the that the weight labeled is 0.3840 pounds and the actual weight is 0.3798 pounds which is lighter than the weight in label. As we see the hundredth place of the decimal of the actual weight is 8 and the labeled weight is 7 which is less than 8.

Thus, the chocolates are heavier than the weight the weight stated on the label.

Now, to get how heavier it is, we subtract the label weight from the actual weight:

$Actual\ weight\ -\ label\ weight.$

$=0.3840\ pounds\ -\ 0.3798\ pounds.$

$=0.0042\ pounds.$

So, the chocolates are 0.0042 pounds heavier.

Therefore, the chocolates are heavier than the weight the weight stated on the label. And the chocolates are 0.0042 pounds heavier.

5 0

3 years ago

Help please, try to explain it in steps for me if u can't that's fine, ty!

Iteru [2.4K]

Answer:

B

Step-by-step explanation:

We are given that Expression One is:

$2\cdot 10^x$

And Expression Two is:

$4\cdot 10^{x+y}$

We are given that the value of Expression Two is 20,000 times greater than the value of Expression One. And we want to find the value of y. In other words:

$4\cdot 10^{x+y}=20000(2\cdot 10^x)$

We can divide both sides by four:

$10^{x+y}=10000\cdot 10^x$

Recall that:

$x^a\cdot x^b=x^{a+b}$

Therefore:

$10^x\cdot 10^y=10000\cdot 10^x$

Divide both sides by 10ˣ:

$10^y=10000$

Solve for y:

$\displaystyle y = \log_{10}10000 = 4$

Our answer is B.

3 0

3 years ago

The Playground Center purchases swing sets for $385.99. It sells the swing sets for $598.99. What is the percent of markup? Roun

denis-greek [22]

Answer:

55%

Step-by-step explanation:

$598.99–$385.99

=$213

$213/$385.99 × 100%

=55%

4 0

3 years ago

A freight train travels at 30 mph. If the freight train is 300 miles ahead of an express train traveling at 55 mph, how long wil

melisa1 [442]

Distance<-------------300--------------><-------------------x----------------->
⊕---------------------------------⊕--------------------------------------⊕ Express Freight Overtaking point
Speed 55 speed 30

Let x be the distance travelled by Freight until the point of overtaking
Time = Distance/Speed, then:

Time (freight) = Distance (fright)/Speed (freight) And
Time (Express) = Distance (Express)/Speed (Express).
Now plug in the relative number:

Time (freight) = x/30 and Time (express) = (x+300)/55. But note that both times are equal, then:
x/30 = (x+300)/55 OR (x÷30 = (x+300)÷55) [Answer C]
Now let's find the distance x. Cross multiplication;

55x= 30(300+x) →55x = 9,000 + 30x
55x - 30x = 9,000 → 25x = 9,000 and x = 9,000/25 = 360 miles
Time needed for Freight to travel 360 m = 360/30= 12 Hours
Time needed for Express to travel (300+360) m = 660/55= 12 Hours
As you see, it's the same time of 12 hours
Don't forget that Distance = Speed x time or time = Distance/Speed, etc.

4 0

3 years ago

Read 2 more answers

Help plz I’m confused

Ilia_Sergeevich [38]

Answer:

C.

Step-by-step explanation:

$\frac{2}{3}$ is between 0 and 1