The answer is 4 diploid cells.
Meiosis is a cell division which results in the reduction of chromosome number by half - from diploid to haploid - in daughter cells. It consists of meiosis I and meiosis II. Meiosis I produces <em>two haploid cells</em>.<span> Meiosis II is analogous to mitosis, so in total, meiosis results in four haploid cells. This is achieved through suppression of DNA replication between two meiotic divisions.
If there were no </span><span>suppression of DNA replication, then meiosis I would produce <em>two diploid cells</em>, and after meiosis II there will be four diploid cells.</span>
The correct answer is c. 3 ' hydroxyl of deoxyribose.
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During the DNA synthesis via PCR, polymerization occurs in 5’-3’ direction. This means that enzyme DNA polymerase which synthesizes a new DNA strand is complementary to the DNA template strand (3’-<span>5’ direction). 5’ phosphate group of the free nucleotides which are added is attached to the 3'-hydroxyl group at the end of the elongating DNA strand.</span></span>
Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16.
When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.
Answer:
The dependent variable would be B, whether or not the men develop baldness.
