Hey there!
Let's think of this with a simpler example. Let's say one package is 4 pounds and one is 2 pounds. How many times heavier is the first than the second?Well, two, because the first package is double the weight of the second package! It's twice as heavy! And to get to that number, we divide four by two!
So, in our actual problem, we just divide 3.92 (bigger package) by 2.8 (smaller package).
3.92÷2.8=1.4
So, the first package is 1.4 times heavier than the first one!
Have a wonderful day!
For the answer to the question above,
z=6-(3/4)y-2x
<span>z+(3/4)y+2x=6 </span>
<span>Just by connecting the three points on the graph, I got this equation by isolating each plane to figure it out. This equation only explains the plane bounded by these three points, though, so to draw it just plot the points and connect them.</span>
Answer: 1,045 passengers
Step-by-step explanation:
This question involves multiple steps. Let's first try to figure the number of children on the cruise.
The ratio of girls to the total number of children was 2:5. There are 198 boys.
This information tells me that for every 5 children, there's 2 girls and 3 boys.
Based off of this information, we can divide the total number of boys by 3 in order to find the number of children.
198÷3=66
Let's multiply 66 by 5 since that's the number of groupings based off the ratio.
66×5=330
Let's check the number of children. Since the ratio of girls to total children is 2:5 and we already confirmed there's 198 boys, there should be 132 girls. We can turn this ratio into a fraction where 2/5 of the children are girls. we can confirm this by multiply 330 by 2/5 (0.4) and getting 132.
There are 330 children on the cruise.
The ratio of the number of adults to the number of children was 13:6.
For every 6 children, there were 13 adults. Let's divide the number of children by 6 in order to find the number of groupings.
330÷6=55
Let's now multiply the groupings by 13 to find the number of adults.
55×13=715
So there should be 715 adults and 330 children on the cruise.
715+330=1,045
First, find any zero of the polynomial. Since you didn't ask for work, I'll assume it's okay if I use my calculator. Your given polynomial has only one real root which is x=-4.
Now we use the rule that x-a divides the polynomial where a is a zero of said polynomial.
So x+4 divides 2x^3+2x^2-19x+20.
<span>(2x^3+2x^2-19x+20) / (x+4 equals 2x^2-6x+5).
If we factor out a two, we can use the quadratic formula.
2(x^2-3x+2.5) so we have x = (-(-3)+/-(9-4*1*2.5)^(1/2))/2*1)=(3+i)... or (3-i)/2 Where i is the square root of negative one. final answer:
2x^3+2x^2-19x+20=0
then x=-4, (3+i)/2, or (3-i)/2
</span>we have two imaginary number.
I hope it helped you
