Using the slope-intercept formula, y=mx+b where m is the slope of the line and b being the y-intercept, by direct substitution, the y-intercept can be directly be obtained,
y=mx+b
14.347 = (4.915)(10.088) + b
therefore, the y-intercept, b = -35.236
We know that the point is in Q II. Thus, the x-coordinate of this point will be negative and the y-coordinate will be positive.
The y-coordinate is essentially given, and is y=4.
Imagine drawing a vertical line thru x=-2. This line will intersect y=4 at (-2,4).
The coordinates of the point are (-2, -4).
So say for example u have -7 - (-5), think of subtracting integers as adding the opposite, so ur adding the opposite of -5, the opposite of -5 is 5, so ur adding -7 and 5= -2
another one: -15 - (-18)
again, adding the opposite. -15 plus positive 18= 3
