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brilliants [131]

4 years ago

7

7 5/8 rounded to the nearest whole #

2 answers:

natita [175]4 years ago

8 0

8 . because if you round to the biggest number it's 8

ivanzaharov [21]4 years ago

8 0

7 5/8
7 * 8 = 56
56 + 5 = 61
61 / 8 = 7.625
When u round 7.625 to the nearest whole it will be 8
Answer: 8

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Help pls... Bonnie has H toys in her room, Y toys lying outside, and B toys from Andy. Write an expression to show the number of

liberstina [14]

Answer:

H+Y+B

Step-by-step explanation:

She has H+Y+B because she has those toys.

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3 years ago

Ahhh if someone can,please answer asap!<br> 20 points!

matrenka [14]

Answer:

x = 32

The 9 and 4 ball are farthest from each other.

Step-by-step explanation:

Since the angles of a triangle add up to 180 degrees, you can create the equation (x-5)+(2x+1)+(3x-8)=180, which can be simplified to 6x-12=180. That means the value of x is 32. That means the 9 ball is at 27 degrees, the 4 ball is at 65 degrees, and the 5 ball is at 88 degrees. Based on the angles, the farthest distance would be between balls 9 and 4.

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3 years ago

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frutty [35]

X= 8

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3 0

3 years ago

Consider the following sets of sample data: A: $30,500, $27,500, $31,200, $24,000, $27,100, $28,600, $39,100, $36,900, $35,000,

Alecsey [184]

Answer:

$CV=0.2$ ---- dataset 1

$CV = 7.2$ --- dataset 2

Step-by-step explanation:

Given

$A: 30500, 27500, 31200, 24000, 27100,28600, 39100, 36900, 35000, 21400, 37900, 27900, 18700,$ $33100$

$B: 4.29, 4.88, 4.34, 4.17, 4.52, 4.80, 3.28, 3.79, 4.84, 4.77, 3.11$

Required

The coefficient of variation of each

<u>Dataset A</u>

Calculate the mean

$\mu = \frac{\sum x}{n}$

$\mu = \frac{30500+ 27500+31200+24000+ 27100+28600+ 39100+ 36900+ 35000+ 21400+ 37900+ 27900+ 18700+33100}{14}$ $\mu = \frac{418900}{14}$

$\mu = 29921.43$

Next, calculate the standard deviation using:

$\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}$

So, we have:

$\sigma= \sqrt{\frac{(30500 - 29921.43)^2 +.................+ (18700- 29921.43)^2 + (33100- 29921.43)^2}{13}}$

$\sigma= \sqrt{\frac{487723571.42857}{14}}$

$\sigma= \sqrt{34837397.959184}$

$\sigma= 5902.32$

So, the coefficient of variation is:

$CV=\frac{\sigma}{\mu}$

$CV=\frac{5902.32}{29921.43}$

$CV=0.2$ --- approximated

<u>Dataset B</u>

Calculate the mean

$\mu = \frac{\sum x}{n}$

$\mu = \frac{4.29+ 4.88+ 4.34+ 4.17+ 4.52+ 4.80+ 3.28+ 3.79+ 4.84+ 4.77+ 3.11}{11}$

$\mu = \frac{46.79}{11}$

$\mu = 4.25$

Next, calculate the standard deviation using:

$\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}$

$\sigma = \sqrt{\frac{(4.29 - 4.25)^2 + (4.88- 4.25)^2 +.........+ (3.11- 4.25)^2}{11}}$

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$\sigma = \sqrt{0.35081818181}$

$\sigma = 0.593$

So, the coefficient of variation is:

$CV=\frac{\sigma}{\mu}$

$CV = \frac{4.25}{0.5903}$

$CV = 7.2$ -- approximated

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3 years ago

A. the tallies are missing

nevsk [136]

Answer:

b I think

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers