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xz_007 [3.2K]
4 years ago
10

Increased industrialization has caused a rise in harmful acid rain precipitation that affects plant and marine life. A sample of

acid rain has a proton concentration 10,000 times greater than pure water and more than 100,000 times greater than seawater. What is the approximate pH of this sample?
Chemistry
1 answer:
wolverine [178]4 years ago
3 0

Answer:

pH of the sample of acid rain is 3.

Explanation:

Pure water has a theoretical pH of 7.00. As pH = -log [H⁺], [H⁺] = 1x10⁻⁷M

Now, the sample of acid rain has a proton concentration 10,000 times greater than pure water. That is:

[H⁺] = 10,000 * 1x10⁻⁷M = 1x10⁻³M

The pH of this sample is:

pH = -log 1x10⁻³M

<h3>pH = 3</h3>
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a) gold-solvent

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solvent- H2O

8 0
3 years ago
In h2o, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a
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3 0
3 years ago
What is the hydrogen ion concentration of a solution with pH=7.75 ?
Alja [10]

Answer:

[H^+]=1.78x10^{-8}M

Explanation:

Hello there!

In this case, according to the given information about the pH, it is firstly necessary for us to remember that the pH is defined as the potential of the hydrogen ions in the solution and the concentration of those ions represents how many of them are present in the solution; in such a way, it is possible for us use:

pH=-log([H^+])

Whereas the concentration of hydrogen ions can be calculated as follows:

[H^+]=10^{-pH}

So we plug in the given pH to obtain:

[H^+]=10^{-7.75}=1.78x10^{-8}M

Regards!

5 0
3 years ago
Calculate the radius ratio for NaBr if the ionic radii of Na + and Br − are 102 pm and 196 pm , respectively. radius ratio: Base
Fudgin [204]

Answer : The expected coordination number of NaBr is, 6.

Explanation :

Cation-anion radius ratio : It is defined as the ratio of the ionic radius of the cation to the ionic radius of the anion in a cation-anion compound.

This is represented by,

\frac{r_{cation}}{r_{anion}}

When the radius ratio is greater than 0.155, then the compound will be stable.

Now we have to determine the radius ration for NaBr.

Given:

Radius of cation, Na^+ = 102 pm

Radius of cation, Br^- = 196 pm

\frac{r_{cation}}{r_{anion}}=\frac{102}{196}=0.520

As per question, the radius of cation-anion ratio is between 0.414-0.732. So, the coordination number of NaBr will be, 6.

The relation between radius ratio and coordination number are shown below.

Therefore, the expected coordination number of NaBr is, 6.

8 0
4 years ago
Help i have no idea what i’m doing and i’m failing this class
m_a_m_a [10]

Answer:

c

Explanation:

esuba is activation energy

8 0
3 years ago
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