1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pie
3 years ago
11

How much energy is needed to raise the temperature of a 200 g piece of lead by 250 o C?

Chemistry
1 answer:
devlian [24]3 years ago
4 0

<u>Answer:</u> The amount of energy required to raise the given amount of temperature is 6400 J

<u>Explanation:</u>

To calculate the heat absorbed by the lead, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of lead = 200 g

c = heat capacity of lead = 0.128 J/g°C

\Delta T = change in temperature = 250°C

Putting values in above equation, we get:

q=200g\times 0.128J/g^oC\times 250^oC=6400J

Hence, the amount of energy required to raise the given amount of temperature is 6400 J

You might be interested in
Which of the following describes how metamorphic rock forms?
nasty-shy [4]

Answer:

well they form by heat and pressure

6 0
3 years ago
Read 2 more answers
I need to someone to explain the whole being of Chemistry. I do not understand a single thing, nothing makes sense to me. Litera
tankabanditka [31]

Answer:

Explanation:

In Pre-AP Chemistry, the development of models to explain their macroscopic observations is a primary means through which students develop an understanding of the molecular world.

You will be forced to think and apply concepts to new situations, and even derive your own theories from application. This is excellent preparation for the higher levels of thinking required in college.

Chemistry, the science that deals with the properties, composition, and structure of substances (defined as elements and compounds), the transformations they undergo, and the energy that is released or absorbed during these processes.

3 0
3 years ago
Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant o
sattari [20]

Answer:

4.26 %

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is  4.50  ×  10 ⁻⁴.</em>

<em />

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50  ×  10 ⁻⁴

Step 2: Write the ionization reaction for nitrous acid

HNO₂(aq) ⇒ H⁺(aq) + NO₂⁻(aq)

Step 3: Calculate the concentration of nitrite in the equilibrium ([A⁻])

We will use the following expression.

[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4}  } = 0.0106 M

Step 4: Calculate the percent ionization of nitrous acid

We will use the following expression.

\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%

4 0
3 years ago
.an open flask contains 0.200 mol of air. atmospheric pressure is 745 mmhg and room temperature is 68˚f. how many moles are pres
aleksklad [387]

<u>0.219 moles </u><u>moles are present in the flask when the </u><u>pressure </u><u>is 1.10 atm and the temperature is 33˚c.</u>

What is ideal gas constant ?

  • The ideal gas constant is calculated to be 8.314J/K⋅ mol when the pressure is in kPa.
  • The ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas.
  • The combined gas law relates pressure, volume, and temperature of a gas.

We simple use this formula-

The basic formula is PV = nRT where. P = Pressure in atmospheres (atm) V = Volume in Liters (L) n =  of moles (mol) R = the Ideal Gas Law Constant.

68F = 298.15K

V = nRT/P = 0.2 * 0.08206 * 298.15K / (745/760) = 4.992Liters

n = PV/RT = 1.1atm*4.992L/(0.08206Latm/molK * 306K)

n = 0.219 moles

Therefore, 0.219 moles moles are present in the flask when the pressure is 1.10 atm and the temperature is 33˚c.

Learn more about ideal gas constant

brainly.com/question/3961783

#SPJ4

4 0
2 years ago
Calculate the heat change involved when 2.00 L of water is heated from 20.0/C to 99.7/C in
IgorC [24]

Answer:

669.48 kJ

Explanation:

According to the question, we are required to determine the heat change involved.

We know that, heat change is given by the formula;

Heat change = Mass × change in temperature × Specific heat

In this case;

Change in temperature = Final temp - initial temp

                                       = 99.7°C - 20°C

                                       = 79.7° C

Mass of water is 2000 g ( 2000 mL × 1 g/mL)

Specific heat of water is 4.2 J/g°C

Therefore;

Heat change = 2000 g × 79.7 °C × 4.2 J/g°C

                      = 669,480 joules

But, 1 kJ = 1000 J

Therefore, heat change is 669.48 kJ

7 0
3 years ago
Other questions:
  • Match each term to its meaning. (3 points)
    5·2 answers
  • Charles Darwin studied finches on the Galapagos Islands. While the finches on all the islands came from the same ancestors, the
    10·2 answers
  • If a sample contains 100.0 g of lead atoms (Pb), how many atoms are present in the sample?
    10·2 answers
  • What determines the reactivity of an akali metal?
    14·1 answer
  • How is a warm front formation diffrent from occlued front formation​
    6·1 answer
  • carbon-dating was performed on an artefact that was found to have 25% of the original carbon-14 remaining in it
    7·1 answer
  • Give one difference between molecule of an element and molecule of a compound with examples​
    9·1 answer
  • Que hace que sea mas probable que un bloque se hunda? Como afecta esto a la densidad del bloque?
    7·1 answer
  • Fill in the blank to complete each statement
    6·2 answers
  • True/false... A molecule makes up a compound explain
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!