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Pie
3 years ago
11

How much energy is needed to raise the temperature of a 200 g piece of lead by 250 o C?

Chemistry
1 answer:
devlian [24]3 years ago
4 0

<u>Answer:</u> The amount of energy required to raise the given amount of temperature is 6400 J

<u>Explanation:</u>

To calculate the heat absorbed by the lead, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of lead = 200 g

c = heat capacity of lead = 0.128 J/g°C

\Delta T = change in temperature = 250°C

Putting values in above equation, we get:

q=200g\times 0.128J/g^oC\times 250^oC=6400J

Hence, the amount of energy required to raise the given amount of temperature is 6400 J

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3 years ago
To break a chemical bond, energy must be(1) absorbed (2) destroyed (3) produced (4) released
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As a chemical bond is formed either by transfer of electrons or sharing of electrons, in order to break the forces of attraction among atoms, energy must be absorbed.

Energy is produced or released when  a chemical bond is formed.

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4 years ago
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2 years ago
F 2.50 × 10−2 g of solid Fe(NO3)3 is added to 100. ML of a 1.0 × 10−4 M NaOH solution, will a precipitate form? (ksp=4 × 10−38 f
vladimir1956 [14]

Answer:

A precipitate will be formed

Explanation:

The Ksp equilibrium of Fe(OH)₃ is:

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And its expression is:

Ksp = 4x10⁻³⁸ = [Fe³⁺] [OH⁻]³

<em>Where the concentrations are concentrations in molarity in equilibrium,</em>

We can write Q as:

Q = [Fe³⁺] [OH⁻]³

<em>Where [] are actual concentrations in molarity of each specie.</em>

<em />

When Q>= Ksp; a precipitate is formed,

When Q< Ksp no precipitate is produced:

[OH⁻] = [NaOH] = 1.0x10⁻⁴M

[Fe²⁺] = 2.50x10⁻²g * (1mol / 179.85g) / 0.100L = 1.39x10⁻³M

<em>179.85g/mol is molar mass of Fe(NO₃)₂ and the volume of the solution is 0.100L = 100mL</em>

<em />

Q = [Fe³⁺] [OH⁻]³

Q = [ 1.39x10⁻³] [ 1.0x10⁻⁴]³

Q = 3.8x10⁻¹⁵

As Q >> Ksp; A precipitate will be formed

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