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3 years ago

How much energy is needed to raise the temperature of a 200 g piece of lead by 250 o C?

Chemistry

1 answer:

devlian [24]3 years ago

4 0

Answer: The amount of energy required to raise the given amount of temperature is 6400 J

Explanation:

To calculate the heat absorbed by the lead, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed

m = mass of lead = 200 g

c = heat capacity of lead = 0.128 J/g°C

$\Delta T$ = change in temperature = 250°C

Putting values in above equation, we get:

$q=200g\times 0.128J/g^oC\times 250^oC=6400J$

Hence, the amount of energy required to raise the given amount of temperature is 6400 J

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It is known that the kinetics of recrystallization for some alloy obey the Avrami equation andthat the value of n in the exponen

Paul [167]

Answer:

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

Explanation:

For Avrami equation:

$y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ k = \dfrac{-In(1-y)}{t^n}$

To calculate the value of k which is a dependent variable for the above equation ; we have:

$k = \dfrac{-In(1-0.40)}{200^{2.5}}$

$k = 9.030 \times 10 ^{-7}$

The time needed for 50% transformation can be determined as follows:

$y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ t =[ \dfrac{-In(1-y)}{k}]^{^{1/n}}$

$t_{0.5} =[ \dfrac{-In(1-0.4)}{9.030 \times 10^{-7}}]^{^{1/2.5}}$

= 200.00183 min

The rate of reaction for Avrami equation is:

$rate = \dfrac{1}{t_{0.5}}$

$rate = \dfrac{1}{200.00183}$

rate = 0.00499 / min

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

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B. Which of these kinds of interactions are broken when a liquid is converted to a gas?

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