Question

How much energy is needed to raise the temperature of a 200 g piece of lead by 250 o C?

Answer 1

Answer: The amount of energy required to raise the given amount of temperature is 6400 J

Explanation:

To calculate the heat absorbed by the lead, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed

m = mass of lead = 200 g

c = heat capacity of lead = 0.128 J/g°C

$\Delta T$ = change in temperature = 250°C

Putting values in above equation, we get:

$q=200g\times 0.128J/g^oC\times 250^oC=6400J$

Hence, the amount of energy required to raise the given amount of temperature is 6400 J