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Vikki [24]
3 years ago
6

Give the balanced chemical equation (including phases) that describes the combustion of butene, C4H8(g). Indicate the phases usi

ng abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively. Express your answer as a chemical equation.
Chemistry
2 answers:
Studentka2010 [4]3 years ago
7 0
Butene is an alkene, which is a hydrocarbon that contains a double bond. At room temperature, butene occurs as a gas. So, when it reacts with oxygen gas, it will yield gaseous products, carbon dioxide and water vapor. The complete balance reaction is written below:

C₄H₈ (g) + 6 O₂ (g) → 4 CO₂ (g) + 4 H₂O (g)
Naddik [55]3 years ago
5 0

Answer:

The chemical equation is given as:

C_4H_8+6O_2(g)\rightarrow 4CO_2(g)+4H_2O(g)

Explanation:

Combustion reaction is the type of chemical reaction in which an organic compound undergoes reaction with oxygen gas to give carbon dioxide and water product.

When butene undergoes combustion reaction it gives carbon dioxide gas and water vapors as a product.

The chemical equation is given as:

C_4H_8+6O_2(g)\rightarrow 4CO_2(g)+4H_2O(g)

According to stoichiometry, 1 mole of butene gas reacts with 6 moles of oxygen gas to give 4 moles of carbon dioxide and 4 moles water vapors.

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How much carbon would be needed to make 8.8g of carbon dioxide?<br>​
PIT_PIT [208]
The calculation for such a question can be achieved via Avogadro hypothesis

We know molar mass of CO2 is 44g/mole which is the sum of atomic masses i.e; C and 2 oxygen atoms

Molar mass of CO2 =12(C)+2*16(O) = 44 g/mole will contain 6.023 ※10^23 CO2 molecules ..

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=> 1g = (6.023/44) ※10^23 CO2 molecules

==> 8.80g = 8.80(6.023÷44)10^23 = 1.2046 ※10^23 molecules of CO2….

Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g

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I don't know if this is helpful or not, but this is what I put if you still needed it.

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