Yes, It is important to know the volume of Unknown acid or base to be titrated.
Titration is carried out in order to find out the concentration (i.e. molarity) of unknown acid or base. In this process a standard solution of acid or base is taken and is titrated with known volume of of titrant. At end point (neutralization) the amount of standard titrant utilized is calculated and following formula is employed to calculate the unknown concentration of unknown solution.
M₁V₁/n₁ = M₂V₂/n₂
Answer:
The half-life of Plutonium 239 (Pu 239) is 24,100 years.
Explanation:
Half-life is the time required for a quantity to reduce to half of its initial value. This means that in 241000 years, 100g of Pu 239 would be reduced to 50g.
Mole ratio:
MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl
2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂
moles Mg(OH)₂ = 4 x 1 / 2
= 2 moles of Mg(OH)₂
molar mass Mg(OH)₂ = 58g/mol
mass of Mg(OH)₂ = n x mm
mass of Mg(OH)₂ = 58 x 2
= 116 g of <span> Mg(OH)₂</span>
hope this helps!
Answer:
The answer is
<h2>4.5 × 10²²</h2>
Explanation:
To find the number of atoms of titanium , given it's number of moles we use the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question
n = 0.075 mol
We have
N = 0.075 × 6.02 × 10²³
We have the final answer as
<h3>4.5 × 10²²</h3>
Hope this helps you