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LenaWriter [7]
2 years ago
15

1) Is coffee hot?

Chemistry
2 answers:
Ksivusya [100]2 years ago
4 0

Answer:

1. not testable

2. testable

3. not testable

4. testable

Sav [38]2 years ago
3 0

Answer:

1. Testable

2. Testable

3. I’d say surfing (just my personal opinion)

4. Testable

Explanation:

I guessed

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A sample of sandstone consists of only silica (SiO2) and calcite (CaCO3). When sandstone is heated, calcium carbonate decomposes
anzhelika [568]

Answer:

0

Explanation:

To calculate, the mass of Carbondioxide is 3.45mg

Then the decomposition of Carbondioxide gives 0 on calculation

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What vesicular transport process do you think is involved in the toxin entering the neuron?
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This is a type of element or substance that is not a metal.
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3 0
3 years ago
Please help me, act fast
monitta

Answer:

10g of Pb.

Explanation:

To know which answer is correct, let us calculate the change in the temperature of each substance. This is illustrated below:

For water:

Mass (M) = 10g

Specific heat capacity (C) = 4.18J/g°C

Change in temperature (ΔT) = ..?

Heat (Q) = 100J

Q = MCΔT

Divide both side by MC

ΔT = Q/MC

ΔT = 100 / (10 x 4.18)

ΔT = 2.4°C

Therefore, the change in the temperature of water is 2.4°C

For Ag:

Mass (M) = 10g

Specific heat capacity (C) = 0.235J/g°C

Change in temperature (ΔT) = ..?

Heat (Q) = 100J

Q = MCΔT

Divide both side by MC

ΔT = Q/MC

ΔT = 100 / (10 x 0.235)

ΔT = 42.6°C

Therefore, the change in the temperature of Ag is 42.6°C

For Ca:

Mass (M) = 10g

Specific heat capacity (C) = 0.650J/g°C

Change in temperature (ΔT) = ..?

Heat (Q) = 100J

Q = MCΔT

Divide both side by MC

ΔT = Q/MC

ΔT = 100 / (10 x 0.650)

ΔT = 15.4°C

Therefore, the change in the temperature of Ca is 15.4°C

For Fe:

Mass (M) = 10g

Specific heat capacity (C) = 0.449J/g°C

Change in temperature (ΔT) = ..?

Heat (Q) = 100J

Q = MCΔT

Divide both side by MC

ΔT = Q/MC

ΔT = 100 / (10 x 0.449)

ΔT = 22.3°C

Therefore, the change in the temperature of Fe is 22.3°C

For Pb:

Mass (M) = 10g

Specific heat capacity (C) = 0.160J/g°C

Change in temperature (ΔT) = ..?

Heat (Q) = 100J

Q = MCΔT

Divide both side by MC

ΔT = Q/MC

ΔT = 100 / (10 x 0.160)

ΔT = 62.5°C

Therefore, the change in the temperature of Pb is 62.5°C

Summary:

Substance >> Change in temperature

Water >>>>>> 2.4°C

Ag >>>>>>>>> 42.6°C

Ca >>>>>>>>> 15.4°C

Fe >>>>>>>>> 22.3°C

Pb >>>>>>>>> 62.5°C

From the calculations made above, Pb has the greatest change in temperature

7 0
3 years ago
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