Answer:
exponential function going through point 0, negative 2 and ending down on the right
Step-by-step explanation:
(Took the test, also seen as "Option A", this graph goes down and hits the y line at 0,-2.)
Answer:
y=-2x^2-4
Step-by-step explanation:
The parabola is wider than it's parent function, y = x^2. Therefore the coefficient, of x^2 (when you refer to quadratic equations it's a) should be greater than 1. Let's take 2.
y = 2x^2
Now it is reflected across the x-axis, so the equation turns to y = -2x^2. The vertex is shifted down 4. Note that it is shifted down, along the y-axis. This makes 'c' (again quadratic equations) -4.
Final Equation: y=-2x^2-4
(h-3k)/2k=-3/4
h-3k=-6k/4
4h-12k=-6k
-12k=-6k-4h
-6k=-4h
Solution: k=2/3h
I hope I helped you with your solution! If you could give me brainliest, I would be very thankful!
Answer:
5 hours
Step-by-step explanation:
127 - 35 = 92
92 / 23 = 4
4 + 1 = 5