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LUCKY_DIMON [66]

3 years ago

5

38.5÷0.5

\div 0.5 = " align="absmiddle" class="latex-formula">

1 answer:

tankabanditka [31]3 years ago

5 0

The answer to the question

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Eric downloads the coupon shown and go shopping at gadgets galore where he buys a digital camera for $95 and an extra battery fo

igomit [66]

There is no coupon shown

8 0

3 years ago

A certain type of thread is manufactured with a mean tensile strength of 78.3 kilograms and a standard deviation of 5.6 kilogram

azamat

Answer:

(a) The variance decreases.

(b) The variance increases.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the sample mean is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The standard deviation of sample mean is inversely proportional to the sample size, <em>n</em>.

So, if <em>n</em> increases then the standard deviation will decrease and vice-versa.

(a)

The sample size is increased from 64 to 196.

As mentioned above, if the sample size is increased then the standard deviation will decrease.

So, on increasing the value of <em>n</em> from 64 to 196, the standard deviation of the sample mean will decrease.

The standard deviation of the sample mean for <em>n</em> = 64 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{64}}=0.7$

The standard deviation of the sample mean for <em>n</em> = 196 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{196}}=0.4$

The standard deviation of the sample mean decreased from 0.7 to 0.4 when <em>n</em> is increased from 64 to 196.

Hence, the variance also decreases.

(b)

If the sample size is decreased then the standard deviation will increase.

So, on decreasing the value of <em>n</em> from 784 to 49, the standard deviation of the sample mean will increase.

The standard deviation of the sample mean for <em>n</em> = 784 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{784}}=0.2$

The standard deviation of the sample mean for <em>n</em> = 49 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{49}}=0.8$

The standard deviation of the sample mean increased from 0.2 to 0.8 when <em>n</em> is decreased from 784 to 49.

Hence, the variance also increases.

6 0

3 years ago

The perimeter of a rectangle is to be no greater than 120 centimeters and the length must be 35 centimeters. Find the maximum wi

Anika [276]

Answer:

25 centimeters

Step-by-step explanation:

120 total perimeter

35 required length

so that leaves us with 2 sides to figure out because if on side length is 35 centimeters then the other side length is 35 centimeters

35 + 35 = 70

120 - 70 = 50

50 / 2 = 25 centimeters

4 0

3 years ago

Find the Sum and the product<br>of the root of the Equadration<br> 1/3and 2/3

Butoxors [25]

Answer:

sorry do not know

Step-by-step explanation:

.

4 0

3 years ago

Read 2 more answers

There are 3 nursing positions to be filled at Lilly Hospital. Position one is the day nursing supervisor; position two is the ni

ZanzabumX [31]

Answer:

2730 possible ways

Step-by-step explanation:

Given

$Applicants = 15$

$Positions = 3$

Required

Number of possible selections

Since there is no restriction, the number of selection is calculated as:

The day nursing supervisor position can be occupied by any of the 15 applicants

The night nursing supervisor position can be occupied by any of the remaining 14

The nursing coordinator position can be occupied by any of the 13

So, the number of ways is then calculated as:

$Ways = 15 * 14 * 13$

$Ways = 2730$

<em>Hence, there are 2730 possible ways</em>

6 0

3 years ago