Answer:
Step-by-step explanation:
<span>it depends how the interest is calculated, but there's not much of a difference
assuming its continuously compouned, you use this formula: A(t)=Pe^(rt), where A is the final amount, P is the initial investment, r is the interest, and t is the time in years
you want to find t such that A(t)=18,600 so 18,600=1000e^(.0675t)
you need to use logarithm to figure it out, take the natural log of both sides
the following properties will come into use:
ln(a*b)=ln(a)+ln(b)
ln(a^b)=bln(a)
ln(e)=1
taking the natural log
ln(18,600)=ln(1000e^(.0675t))
ln(18,600)=ln(1000)+ln(e^.0675t)
ln(18600)=ln(1000) + .0675t
now solve for t: t= (ln(18600)-ln(1000))/.0675
t=43.31</span>
Answer:
131.87-23.24=108.63
Step-by-step explanation:
To solve this problem, let's line up the problem. To make it easier, we can start by ignoring the decimals.
13187
- 2324
______
10863
And then, since there were decimals in the first place, we have to add them back in.
10863→108.63
in any case, the amount of zeros is more important than the significant digits. since 7X10-9 has a smaller exponent above the 10 than 6X10-4, it is safe to say 6X10-4 is the larger number
