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RSB [31]
3 years ago
10

What is the best way to put out a clothing fire started by electrical equipment? pouring water on the equipment unplugging all o

f the equipment plugging in a fan and blowing away the fire using a fire blanket to smother the flames
Physics
2 answers:
Andre45 [30]3 years ago
4 0

Answer:

D. Using a fire blanket to smother the flames

Explanation:

Just took the quiz and this is correct.

Leona [35]3 years ago
3 0
<u>Answer</u>
<span>unplugging all of the equipment

<span><u>Explanation</u>
</span></span>In any fire accidents one should first determine the source and attack there first. <span>
Since the fire is as a result of electrical equipment, the first thing should be to cut out the flow of current. 
Water been a good conduct of current is should never be used to out off fire started by electrical equipment. 
By blowing or using fun, this would spreed the fire more. 
The best answer that suits this question is </span>unplugging all of the equipment.

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miniature spring-loaded, radio-controlled gun is mounted on an air puck. The gun's bullet has a mass of 5.00 g, and the gun and
Tamiku [17]

Answer:

12 m/s

Explanation:

From the question,

Applying the law of conservation of momentum,

total momentum before collision = Total momentum after collision

mu+Mu' = mv+Mv'........................... Equation 1

Where m = mass of the bullet, u = initial velocity of the bullet, M = combined mass of the gun and the puck, u' = initial velocity of the gun and the puck, v = final velocity of the bullet, v' = final velocity of the gun and the puck

make v the subeject of the equation

v = [(mu+Mu')-Mv']/m................. Equation 2

Given: m = 5.00 g = 0.005  kg, M = 120 g = 0.12 kg, u = u' = 0 m/s (at rest), v' = 0.5 m/s

Substitute these values into equation 2

v = [0-(0.12×0.5)]/0.005

v = -0.06/0.005

v = -12 m/s

The negative sign  can be ignored since we are looking for the speed, which has only magnitude.

Hence the speed of the bullet is 12 m/s

5 0
3 years ago
Rahul and Sonia were playing with blocks and each of them made a train out of them. Both of them thought of measuring the length
lozanna [386]

Answer:

They measured their train using their handspan

7 0
3 years ago
To initiate a nuclear reaction, an experimental nuclear physicist wants to shoot a proton into a 5.50-fm-diameter 12C nucleus. T
Fantom [35]

Answer:

V_1= 3.4*10^7m/s

Explanation:

From the question we are told that

Nucleus diameter d=5.50-fm

a 12C nucleus

Required kinetic energy K=2.30 MeV

Generally initial speed of proton must be determined,applying the law of conservation of energy we have

            K_2 +U_2=K_1+U_1

where

K_1 =initial kinetic energy

K_2 =final kinetic energy

U_1 =initial electric potential

U_2 =final electric potential

mathematically

   U_2 = \frac{Kq_pq_c}{r_2}

where

r_f=distance b/w charges

q_c=nucleus charge =6(1.6*10^-^1^9C)

K=constant

q_p=proton charge

Generally kinetic energy is know as

         K=\frac{1}{2}  mv^2

Therefore

         U_2 = \frac{Kq_pq_c}{r_2} + K_2=\frac{1}{2}  mv_1^2 +U_1

Generally equation for radius is d/2

Mathematically solving for radius of nucleus

         R=(\frac{5.50}{2}) (\frac{1*10^-^1^5m}{1fm})

         R=2.75*10^-^1^5m

Generally we can easily solving mathematically substitute into v_1

   q_p=6(1.6*10^-^1^9C)

   K_1=9.0*10^9 N-m^2/C^2

   U_1= 0

   R=2.75*10^-^1^5m

   K=2.30 MeV

   m= 1.67*10^-^2^7kg

   V_1= (\frac{2}{1.67*10^-^2^7kg})^1^/^2 (\frac{(9.0*10^9 N-m^2/C^2)*(6(1.6*10^-^1^9C)(1.6*10^-^1^9C)}{2.75*10^-^1^5m+2.30 MeV(\frac{1.6*10^-^1^3 J}{1 MeV}) }

    V_1= 3.4*10^7m/s

Therefore the proton must be fired out with a speed of V_1= 3.4*10^7m/s

8 0
3 years ago
Noah stands 170 meters away from a steep canyon wall. He shouts and hears the echo of his
bezimeni [28]
340 ms


I got it right and I hope you do as well
6 0
3 years ago
Heat is also called
Mrac [35]
Thermal energy (any word that begins with therm has to do with heat)
6 0
3 years ago
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