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3 years ago

PLEASE THIS IS DUE AT MIDNIGHT LOL:

Mathematics

2 answers:

Bingel [31]3 years ago

7 0

Answer:

186.55 mph

Step-by-step explanation:

Let the speed of the plane be s

The speed of the plane in the same direction is

s + 12

The speed of the plane against wind is

s - 12

Time = distance/speed

455/(s + 12) = 400/(s - 12)

Solving for s

400(s + 12) = 455(s - 12)
400s + 400*12 = 455s - 455*12
455s - 400s = (400 + 455)*12
55s = 10260
s = 10260/55
s = 186.55 mph

Free_Kalibri [48]3 years ago

4 0

if a plane flies 455 miles with wind, and takes 400 against the wind, and the wind is blowing at a speed of 12mph, then the plane can fly 2455 miles if it's still in the air

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A random sample of 300 circuits generated 13 defectives. Use the data to test the hypothesis Upper H Subscript 0 Baseline colon

____ [38]

Complete Question

A random sample of 300 circuits generated 13 defectives. a. Use the data to test

$H_o : p = 0.05$

Versus

$H_1 : p \ne 0.05$

Use α = 0.05. Find the P-value for the test

Answer:

The p-value is $p-value = 0.5949$

Step-by-step explanation:

From the question we are told that

The sample size is n = 300

The number of defective circuits is k = 13

Generally the sample proportion of defective circuits is mathematically represented as

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{13}{300}$

=> $\^ p = 0.0433$

Generally the standard Error is mathematically represented as

$SE = \sqrt{\frac{p(1- p)}{n} }$

=> $SE = \sqrt{\frac{0.05(1- 0.05)}{300} }$

=> $SE = 0.0126$

Generally the test statistics is mathematically represented as

$z = \frac{\^ p - p }{SE}$

=> $z = \frac{0.0433 - 0.05 }{0.0126}$

=> $z = -0.5317$

From the z table the area under the normal curve to the left corresponding to -0.5317 is

$(P < -0.5317 ) = 0.29747$

Generally the p-value is mathematically represented as

$p-value = 2 * P(Z < -0.5317 )$

=> $p-value = 2 * 0.29747$

=> $p-value = 0.5949$

3 0

3 years ago

Will give brainiest for this

cluponka [151]

Answer:

lol, u can still ask the question

Step-by-step explanation:

3 0

3 years ago

Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th

DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that $A \cap B$ = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

$A + (A \cap B) = 0.40$

$A + 0.17 = 0.40$

$A = 0.23$

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

$B + (A \cap B) = 0.35$

$B + 0.17 = 0.35$

$B = 0.18$

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0

3 years ago

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Ivan

You planned on making 5000 cookies

4 0

3 years ago

An auto insurance company has 10,000 policyholders. Each policy is defined as: young or old male or female; and married or singl

Blababa [14]

Answer:

880

Step-by-step explanation:

This problem a bit annoying, but let's classify the numbers and see where we can get from there:

Total = 10,000

Young = 3,000

Old = 7,000 (not young defined as 10,000 - 3,000)

Male = 4,600

Female = 5,400

Married = 7,000

Single = 3,000

Young Males = 1,320

Young Females = 3,000 (young) - 1,320 = 1,680

Married Males = 3,010

Married Females = 7,000 - 3,010 = 2,990

Young Married = 1,400

Young Married Males = 600

Young Married Females = 1,400 - 600 = 800

Young Female Single = ?

Young Female = 1,680 from above. But not all of them are single.

Young Married Females = 800 from above

Young Female Single = Young Female - Young Married Females = 1,680 - 800 = 880

6 0

3 years ago