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vesna_86 [32]
3 years ago
7

PLEASE THIS IS DUE AT MIDNIGHT LOL:

Mathematics
2 answers:
Bingel [31]3 years ago
7 0

Answer:

  • 186.55 mph

Step-by-step explanation:

Let the speed of the plane be s

<u>The speed of the plane in the same direction is</u>

  • s + 12

<u>The speed of the plane against wind is</u>

  • s - 12

<u>Time = distance/speed</u>

  • 455/(s + 12) = 400/(s - 12)

<u>Solving for s</u>

  • 400(s + 12) = 455(s - 12)
  • 400s + 400*12 = 455s - 455*12
  • 455s - 400s = (400 + 455)*12
  • 55s = 10260
  • s = 10260/55
  • s = 186.55 mph
Free_Kalibri [48]3 years ago
4 0

if a plane flies 455 miles with wind, and takes 400 against the wind, and the wind is blowing at a speed of 12mph, then the plane can fly 2455 miles if it's still in the air

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Step-by-step explanation:

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\tan(a)  +  \tan(b)  +  \tan(c)  \\  =  \tan(a)  +  \tan(b)  -  \tan(a + b)  \\  =  \tan( a)  +  \tan(b)  -  \frac{ \tan(a) +  \tan(b)  }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{ ( \tan(a) +  \tan(b)  ) \tan(a) \tan(b)  }{ \tan(a) \tan(b)  - 1 } (1)

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\tan(a)  \tan(b)  \tan(c)  \\  =  -  \tan(a)  \tan(b)  \tan(a + b)  \\  =  \frac{ -(\tan( a  )   + \tan(b) ) \tan(a)  \tan(b) }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{( \tan(a)  +  \tan(b)) \tan(a)   \tan(b) }{ \tan(a) \tan(b)  - 1 } (2)

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