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PSYCHO15rus [73]
3 years ago
7

I need a honest and correct answer ASAP please:)

Biology
1 answer:
Bad White [126]3 years ago
3 0

the answer to this question is false

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. Your lab technician was to determine the ash content of buttermilk by conventional dry ashing. The technician weighed 5 g of l
expeople1 [14]

Answer:

Ashing process is done to evaluate the ash content present in petroleum or other proucts, so that they can be used for certain applications

The two major types of ashing process that includes dry ashing and wet ashing and can be performed using microwave systems or conventional means.

a. errors made in the preceding method while determining the ash content of buttermilk by conventional dry ashing are as following:

  • Buttermilk should not immediatly put into muffle immediatley, it should be boiled first to avoid splatter.
  • Temperature should be between 500 to 600 degree celcius at high temperature teh ash content can be loss.
  • The sample should be ashed for 12-18 hrs , more than this can damage the required ash content.
  • platinum tip should be used in place of stainless steel because platinum has a lower concomitant tip impedance than stainless stell, so less reactive to ash.
  • The ash should put in dessicator and not allow to kept in open because ash can react with the humidity in teh atmosphere.

b. The result that occur due to above errors such as the temperature, time,  tongs and leaving ash in open will manipulate the final ash content and its application can be harmful for humans and for other purpose if it will be used.

5 0
3 years ago
1.) You are studying P120, a protein of 120 KDa that is continuously synthesized in eukaryotic cells. Its cellular concentration
irina1246 [14]

Answer:

1. P120 is degraded in the 26S proteasome

2. The 26S proteasome has a major role in protein degradation and is critical for protein homeostasis

3. Cell cycle and DNA replication are cellular processes regulated by the Ras and NFkB pathways

Explanation:

The proliferation-associated nucleolar protein (p120) is a protein known to be expressed during the interphase of the cell cycle, specifically in G1 and early S phase, where any problem with DNA replication trigger a checkpoint, i.e., a molecular cascade of signaling events that suspend DNA replication until the problem is resolved. In mammalian cells, the 26S proteasome is responsible for catalyzing protein degradation of about 80% (or even more) of their proteins. The 26S proteasome acts to degrade rapidly misfolded and regulatory proteins involved in the cell cycle, thereby having a major role in protein homeostasis and in the control of cellular processes. It is for that reason that inhibitors that block 26S proteasome function have shown to be useful as therapeutic agents in diseases associated with the failure of protein degradation mechanisms (e.g., multiple myeloma). The NF-κB are highly conserved transcription factors capable of regulating different cellular processes including, among others, cellular growth, inflammatory responses and apoptosis. Moreover, the MAPK/ERK pathway is able to transduce different signals received on the cell surface to the nucleus. The MAPK/ERK pathway is activated when a singling molecule binds to a cell receptor which triggers a signaling cascade that ends when a transcription factor induces the expression of target genes, ultimately producing a response in the cell (for example, the progression through the cell cycle).

7 0
3 years ago
What is the difference between forward spatter and back spatter?
pashok25 [27]
Forward spatter is the blood that is ejected out of the exit wound,going the same direction as the bullet.back spatter is the blood ejected out of the entry wound,travelling against the line of fire and towards the shooter.
4 0
3 years ago
The hypothalamus secretes __________, which are classified as _________ hormones, whereby they increase the secretion of an ante
anygoal [31]
The answer is <span>neurohormones; releasing; inhibiting</span>
6 0
3 years ago
Free palmitate is activated to it's coA derivative(palmitoyl-CoA) in the cytosol before it can be oxidized in the mitochondria.
n200080 [17]

Answer: hydrolysis of intermediate palmitoyl Co A ,with loss of labeled CoA.before reaching the matrix gives the answer

Explanation:

This is because when the labeled Coenzyme A of the Plamitate combines as Palmitoy-CoA with oxaloacetate to form intermediate (palmitoyl-CoA )in Citric Acid cycle:

CoA is hydrolysed with loss of the labelled CoA which returns to the cystosol. Therefore, the labelled CoA does not reach the matrix of the mitochondrial,but returns to the Cystosol.

Consequently, the CoA in the Cystosol will be labelled in palmitoylCoA and the one in the matrix of the liver mitochondrial will be non radioactive(,will not labelled).

7 0
3 years ago
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