Vertex form is y = -(x+4)^2+9
What is the interquartile range of the data? 24, 25, 27, 36, 37, 42, 42, 43, 49, 49, 50, 53, 59, 61, 65 41 7 17 10
AysviL [449]
<span>The interquartile range is the difference between the third quartile and the first quartile. First, find the median so you can separate the data in half. The median is the middle number. Arrange the numbers from least to greatest and find the number in the middle.
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Find the medians of these two halves. These will be Quartile 1 and Quartile 3.

Quartile 1 is 36

Quartile 3 is 53
Answer:
-1/11
Step-by-step explanation:
add 1/6 to both sides
make the same denominator 12 on the right side
solve
multiply by 12 both sides
11x= -1 divide by 11
x= -1/11
It would be: y-y1 = m(x-x1)
y-8 = m(x+16)
y-8 = mx+16m
y = mx+16m+8
you have to calculate m, which can be possible if two coordinates are given otherwise it's the final possible answer...