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3 years ago

How do you determine if 5x-7y=14 is a function?

2 answers:

6 0

You can type that function in a graphing calculator and either see the graph or the table. If you put that function in a table, then you have to make sure that x isn't repeating itself. If you look at the graph, then you have to do the vertical line test

Pavlova-9 [17]3 years ago

3 0

One way is to graph it and do the vertical line test
it is not a function if we can draw a vertical line in the graph that passes through 2 points of the graph

if we graph this function, we see there is no place we can draw a vertical line and hit the line twice

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3 years ago

I want to know the answer to the sum of f and 6

11111nata11111 [884]

f + 6 = ?

Well, the answer can be pretty much any number. It all depends on what number f is. f is a variable, so you can plug in any number to replace f.

For example, if f was 5, this is what the equation would look like:

5 + 6 = 11

If f was -3, this is what the equation would look like:

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4 0

3 years ago

A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline

dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So $P(B) = 0.35$

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

$P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125$

Probability

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667$

46.67% probability that they flew with airline B.

5 0

3 years ago