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Gekata [30.6K]
3 years ago
11

Write an equation, in slope intercept form, that passes through the points (-16,8 )

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0

It would be: y-y1 = m(x-x1)

y-8 = m(x+16)

y-8 = mx+16m

y = mx+16m+8

you have to calculate m, which can be possible if two coordinates are given otherwise it's the final possible answer...

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A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/
xz_007 [3.2K]

Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016

The degrees of freedom for this sample size are:

df=n-1=25-1=24

The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.318 \cdot 0.016=0.021

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186

The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).

6 0
3 years ago
I NEED THE ANSWER FOR NUMBER 1
garik1379 [7]

Answer:

Answer would be x=1.

Step-by-step explanation:

7 0
3 years ago
Find the quotient of 3 2/5 and 3 1/6 . Express your answer in simplest form.
ladessa [460]
Decimal Form: 1.07
Mixed Number:1 7/95


3 0
4 years ago
Read 2 more answers
What is the length of RS.
Natali [406]

Consider, in ΔRPQ,

RP = R (Radius of larger circle)

PQ = r (radius of smaller circle)

We have to find, RQ, by Pythagoras theorem,

RP² = PQ²+RQ²

R² = r²+RQ²

RQ² = R²-r²

RQ = √(R²-r²

Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ

RS = 2√(R²-r²)

5 0
3 years ago
And now
shtirl [24]

Answer:

I know another one

Step-by-step explanation:

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