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grin007 [14]
3 years ago
7

can you write an equation by setting an expression equal to itself. would an equation like this be true

Mathematics
2 answers:
Rashid [163]3 years ago
8 0

Of course !  An expression is <u>always</u> equal to itself.

But if there's, say, an 'x' in the expression, then such an equation would be true
for x=every possible number.  You might say it has an infinite number of solutions ...
which certainly has to be true, because no matter what you do to an expression,
it's still always equal to itself !

 
tensa zangetsu [6.8K]3 years ago
4 0
Yes it would be as long as it truly equals eachother
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nata0808 [166]

Answer:

42

Step-by-step explanation:

<u>Area of triangle:</u>

A = 1/2bh

A = 1/2(2)(3)

A = 3

<u>Area of rectangle:</u>

A = bh

A = 11(3)

A = 33

<u>Area of triangle:</u>

A = 1/2bh

A = 1/2(3)(4)

A = 6

<u>Combined:</u>

3 + 33 + 6

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8 0
3 years ago
Select the functions that have a value of -1. sin180° cos180° tan180° csc180° sec180° cot180°
kupik [55]

We have to break each degree in terms of 90

A) sin180^\circ=sin(90\times2+0)

Which is in third quadrant, therefore sine is negative hence

sin(90\times2+0)= -sin0 ^\circ = 0


B) cos180^\circ =cos(90\times2+0)

Which is in third quadrant, therefore cosine is negative hence

cos(90\times2+0)= -cos0^\circ  = -1


C) tan180^\circ=tan(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

tan(90\times2+0)= tan0^\circ  = 0


D) csc180^\circ=csc(90\times2+0)

Which is in third quadrant, therefore cosec is negative hence

cosec(90\times2+0)= -csc0^\circ  =not defined


E)sec180^\circ=sec(90\times2+0)

Which is in third quadrant, therefore secant is negative hence

sec(90\times2+0)= -sec0^\circ  = -1


F) cot180^\circ=cot(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

cot(90\times2+0)= cot0^\circ = not defined


Hence only cos 180^\circ and

sec180^\circ have value -1

Hope this will help

7 0
3 years ago
Solve for x by finding the missing side of the triangle. Round your answer to the nearest tenth.
MAXImum [283]

Answer:

<h3>x = 22.54</h3>

Step-by-step explanation:

Tangent θ = Opposite / Adjacent

tan(29) = 20/x

Cross multiply.

x = 20 / (tan(29))

x = 22.544284

4 0
3 years ago
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Flura [38]

Answer:

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Step-by-step explanation:

g(x)=60(1-0.5)^x, g(4)

g(4)=60(1-0.5)^4

g(4)=60(.5)^4

g(4)=60(0.0625)

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7 0
3 years ago
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Flauer [41]

Answer:

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Step-by-step explanation:

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