Suzie wants to buy a shirt that costs $30.00. She has $90.00. How many shirts can Suzie buy?

Mathematics

2 answers:

aivan3 [116]3 years ago

6 0

Answer:

3 shirts

Step-by-step explanation:

90 divided by 30 = 3

Therefore, with $90.00, Suzie can buy 3 shirts.

amm18123 years ago

4 0

Answer:

3 shirts

Step-by-step explanation:

$90/$30=3 shirts

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Yall pls help meeeee (brainliest btw)!!!!!

Korvikt [17]

<h2>Answer:</h2>

Let m be the amount each mom can paint and d be the amount each daughter can paint.

On the first day, 8 mothers were painting so the mothers painted 8m square feet. 12 daughters also painted so the daughters painted 12d square feet. The total amount painted on the first day is then 8m+12d square feet. Since 220 square feet was painted on the first day, then 8m+12d=220. Dividing both sides by 4 gives a simplified equation of 2m+3d=55.

On the second day, 6 mothers were painting so the mothers painted 6m square feet. 8 daughters also painted so the daughters painted 8d square feet. The total amount painted on the second day is then 6m+8d square feet. Since 152 square feet was painted on the second day, then 6m+8d=152

Multiply the first equation by -3 and then add it to the second equation to eliminate m and solve for d:

d=13

2m+3d=55

2m+3(13)=55

2m+39=55

2m=16

m=8

Therefore each mom painted 8 square feet and each daughter painted 13 square feet.

4 0

3 years ago

A random sample of 4000 college students yielded 2250 who are in favor of banning Hawaiian shirts. Estimate the true proportion

Andreas93 [3]

Answer: (0.5496, 0.5754)

Step-by-step explanation:

The confidence interval for population proportion (p) is given by :-

$\hat{p}\pm z*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$ , where $\hat{p}$ = Sample proportion , n= sample size , z*= Critical z-value.

Let p be the proportion of all college students who are in favor of banning Hawaiian shirt.

Given, A random sample of 4000 college students yielded 2250 who are in favor of banning Hawaiian shirts.

i.e. n=4000

$\hat{p}=\dfrac{2250}{4000}=0.5625$

z-value for 90% confidence level is 1.645

Now , 90% confidence interval for p would be :

$0.5625\pm (1.645)(\sqrt{\dfrac{0.5625(1-0.5625)}{4000}})$

$=0.5625\pm (1.645)(\sqrt{0.0000615234375})\\\\=0.5625\pm (1.645)(0.00784368774876)\\\\\approx0.5625\pm0.0129\\\\=(0.5625-0.0129, \ 0.5625+0.0129)\\\\=(0.5496,\ 0.5754)$