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horrorfan [7]
3 years ago
13

Suzie wants to buy a shirt that costs $30.00. She has $90.00. How many shirts can Suzie buy?

Mathematics
2 answers:
aivan3 [116]3 years ago
6 0

Answer:

3 shirts

Step-by-step explanation:

90 divided by 30 = 3

Therefore, with $90.00, Suzie can buy 3 shirts.

:)

amm18123 years ago
4 0

Answer:

3 shirts

Step-by-step explanation:

$90/$30=3 shirts

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Solve the equation for x.<br> X +9= -11
Vera_Pavlovna [14]

Answer:

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Step-by-step explanation:

x+9=-11

Subtract 9 from both sides. (-11-9=-20)

x=-20

7 0
3 years ago
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National data indicates that​ 35% of households own a desktop computer. In a random sample of 570​ households, 40% owned a deskt
Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a​ desktop.

Step-by-step explanation:

We are given that National data indicates that​ 35% of households own a desktop computer.

In a random sample of 570​ households, 40% owned a desktop computer.

<em><u>Let p = population proportion of households who own a desktop computer</u></em>

SO, Null Hypothesis, H_0 : p = 25%   {means that 35% of households own a desktop computer}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 570​ households who owned a desktop computer = 40%

            n = sample of households = 570

So, <u><em>test statistics</em></u>  =  \frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }

                               =  2.437

<em>Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.</em>

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

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3 years ago
I need help on this question
tester [92]
A i guess i just need points
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3 years ago
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densk [106]
<h2><u>D:</u></h2><h2><em /></h2><h2><em>The awnser is </em><u><em>4</em></u><em>!! Hope this helps!! <3</em></h2>
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Your answer is going to be

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