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sergejj [24]
3 years ago
11

Round 35,894 to the greatest place

Mathematics
2 answers:
laiz [17]3 years ago
7 0
35,894 rounded to the greatest place is 36,000
amid [387]3 years ago
4 0
Hoping that I rounded it to the right place. 
It would be 35,900
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Jet001 [13]

Answer:

  • 15 inches

Step-by-step explanation:

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  • b = a√3 = 5√3 *√3 = 5*3 = 15
7 0
2 years ago
describe how the location of the vertex of the angle determines the process of finding the angle measures associated with that a
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Step-by-step explanation:

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3 years ago
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Semmy [17]

Answer:

Step-by-step explanation:

54, 1\frac{2}{3} , 1, 0.5, 0.03, 0, - 1, - 1\frac{3}{4} , - 4, - 103

5 0
3 years ago
Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.
lakkis [162]

Answer:

2*sin(x)+y*cos(x)-cos(y)=C_1

Step-by-step explanation:

Let:

P(x,y)=2*cos(x)-y*sin(x)

Q(x,y)=cos(x)+sin(y)

This is an exact differential equation because:

\frac{\partial P(x,y)}{\partial y} =-sin(x)

\frac{\partial Q(x,y)}{\partial x}=-sin(x)

With this in mind let's define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x}=P(x,y)

and

\frac{\partial f(x,y)}{\partial y}=Q(x,y)

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y)

f(x,y)=\int\  2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}

Now, let's replace the previous result into \frac{\partial f(x,y)}{\partial y}=Q(x,y) :

cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)

Solving for \frac{dg(y)}{dy}

\frac{dg(y)}{dy}=sin(y)

Integrating both sides with respect to y:

g(y)=\int\ sin(y)  \, dy =-cos(y)

Replacing this result into f(x,y)

f(x,y)=2*sin(x)+y*cos(x)-cos(y)

Finally the solution is f(x,y)=C1 :

2*sin(x)+y*cos(x)-cos(y)=C_1

7 0
3 years ago
Expand the following:<br> a) x(x + 2)<br> b) x(2x - 5)<br> c) 2x(3x + 4)<br> d) 6x(x - 2)
TEA [102]

Answer:

<h2>a. \:  {x}^{2}  + 2</h2>

<h2> </h2><h2>b. \: 2 {x}^{2}  - 5x</h2><h2> </h2><h2>c. \: 6 {x}^{2}  + 8x</h2><h3> </h3><h3>d. \: 6 {x}^{2}  - 12x</h3>

solution,

a. \: x(x + 2) \\  \:  \:  = x \times x + 2 \times x \\  \:  \:  =  {x}^{2}  + 2x

b . \: x(2x - 5) \\  \:  = x \times 2x - x \times 5 \\  \:  \:  = 2 {x}^{2}  - 5x

c. \: 2x(3x + 4) \\  \:  = 2x \times 3x + 2x \times 4 \\  \:  \:  = 6 {x}^{2}  + 8x

d. \: 6x(x - 2) \\  \:  \:  = 6x \times x  - 6x \times 2 \\  \:  \:  = 6 {x}^{2}  - 12x

<h2> </h2><h2 />

Hope this helps...

Good luck on your assignment..

4 0
3 years ago
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