For cosФ×sinФ =0, then either cosФ or sin Ф must be zero.
cos 90 = cos 270 = 0
sin 0 = sin 180 = sin 360 = 0.
So, the values that would give you 0 are:
1. cos 90 sin Ф
2. cos 270sin Ф
3. cos Ф sin 0
4. cos Ф sin 180 and
5 cos Ф sin 360.
Jessica tipped the driver about $4.75 or $4.756
Answer:
For number 13, I think it is rational, integer, and whole number
The graph of the circle equation is graph (d)
<h3>How to determine the circle?</h3>
The equation is given as:
x^2 + y^2 - 4x + 9y -7 = 0
Rewrite as:
x^2 - 4x + y^2 + 9y = 7
Express (x^2 - 4x) and (y^2 + 9y) as perfect squares.
So, we have:
(x - 2)^2 + (y + 3)^2 = 7 + 4 + 20.25
Evaluate the sum
(x - 2)^2 + (y + 3)^2 = 31.25
A circle equation is represented as:
(x - h)^2 + (y - k)^2 = r^2
Where
Center = (h, k)
Radius = r
So, we have:
(h, k) = (2, -3)
r^2 = 31.25
r = 5.5
The circle that has a center of (2, -3) and a radius of 5.5 is graph d
Hence, the graph of the circle equation is graph (d)
Read more about circle equation at:
brainly.com/question/1559324
#SPJ1
Explanation:
Differentiating the solution, we have ...
y' = c1 +8c2x^7
y'' = 56c2x^6
Putting this into the DE, we have ...
x^2y'' -8xy' +8y = 16 . . . . . . . different from your problem statement
x^2(56c2x^6) -8x(c1 +8c2x^7) +8(c1x +c2x^8 +2) = 16
56c2x^8 -8c1x -64c2x^8 +8c1x +8c2x^8 +16 = 16
x^8(56c2 -64c2 +8c2) +x(-8c1 +8c1) +16 = 16
0 +16 = 16 . . . . QED
