Three Types of Solutions of a System of Linear Equations. There are three possible outcomes for a system of linear equations: one unique solution, infinitely many solutions, and no solution. This video shows an example of each type of outcome.
The answer is B. Force=mass X accleration
Answer:
2.15 m/s²
Explanation:
We'll begin by calculating the force of attraction between two charges. This can be obtained as follow:
Charge of 1st object (q₁) = +11.5 μC = +11.5×10¯⁶ C
Charge of 2nd object (q₂) = –7.55 μC = –7.55×10¯⁶ C
Electrical constant (K) = 9×10⁹ Nm²/C²
Distance apart (r) = 0.925 m
Force (F) =?
F = Kq₁q₂ / r²
F = 9×10⁹ × 11.5×10¯⁶ × 7.55×10¯⁶/ 0.925²
F = 0.781425 / 0.855625
F = 0.91 N
Finally, we shall determine the acceleration of the object. This can be obtained as follow:
Mass of object (m) = 0.423 Kg
Force (F) = 0.91 N
Acceleration (a) =?
F = ma
0.91 = 0.423 × a
Divide both side by 0.423
a = 0.91 / 0.423
a = 2.15 m/s²
Thus, the magnitude of the object's acceleration is 2.15 m/s²
This is a sneaky trick question, to help you discover whether you know
one of the differences between velocity and speed.
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If you make a list of the distances and directions, and ignore the times,
you find these:
4 - west, (3 + 1) - east . . . . . zero in the east/west direction
1.5 - north, 1.5 - south . . . . . zero in the north/south direction
This jogger went out, had a nice jog around the neighborhood,and ended up exactly where he started.
Average velocity = (distance between start point and end point) / (time)
IF the question asked for average SPEED, then you would need the total distance, and divide it by the total time. But it asks for VELOCITY, and <u>that</u> only involves the straight distance between the start point and the end point, regardless of the route taken in between.
The jogger ended up exactly where he started. The distance between start and end points was zero. Average velocity is (zero) / (time) . And that fraction is going to be <em><u>Zero</u></em>, no matter how long or how short the trip was, and no matter how much time it took.
Answer:
The difference of power is
ΔP = 172.767 kPa
Explanation:
ρ = 1390 kg / m³
v = 9.63 m/s
d₁ = 10.1 cm , d₂ = 15.3 cm
Δz = 8.85 m
To find the difference ΔP between the fluid pressure at locations 2 and the fluid pressure at location 1
ΔP = ρ * g * Z + ¹/₂ * ρ * v² * ( 1 - (d₁ / d₂)⁴ )
ΔP = 1390 kg / m³ * 9.8 m/s² * 8.85 m + 0.5 * 1390 kg / m³ *(9.63 m /s)² * (1 - (0.101 m / 0.153 m )⁴ )
ΔP = 172.767 x 10 ³ Pa
ΔP = 172.767 kPa