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expeople1 [14]
3 years ago
11

When objects exchange charge, why do we say it's the negative charge that moves and not the positive?

Physics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

It is said that the negative charge moves because the electrons in the atoms of any object are taken or given to the atoms of another object.

Explanation:

The atom is made up of protons, electrons and neutrons. The number of protons is exactly the same to the number of electrons for a certain element. For example, hydrogen: it has a proton, and therefore, an electron.

The electron has a negative charge. The proton has a positive charge. And the neutron has no charge, so it is neutral. While the atom has the same number of protons and electrons, it will not be electrically charged.

An example of how a charge exchange occurs between two objects is through the case of rubbing. This makes the atoms of the two objects close enough that there is an electron transfer, causing any of the objects to gain or lose electrons as a consequence of each other interaction. In the case of transferring electrons, the atom will have a greater number of protons, so it will be positively charged. When the atom receive electrons, it will have a greater number of electrons, so it will be negatively charged.

Therefore, since it is the electrons that move from one atom to another, then it is the negative charge that moves (<em>characterized by the electrons</em>) and not the positive charge (<em>characterized by the protons</em>).

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Answer:

new moon

Explanation:

A solar eclipse take place at new moon phase, when the moon passes between the earth and the sun and its shadows fall on the Earth's surface which by definition a solar eclipse.

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A car travels 1.7 km in the x-direction, then turns left 63.4° to the original direction and travels an additional distance of 3
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1.7 km + cos(63.4) * 3.25 km = 3.16 km

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A solar eclipse occurs when the A solar eclipse occurs when the the moon's shadow touches Earth. moon passes into the Earth's sh
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Answer:

There will always be a shadow created by the sun shining on the moon.

When the earth is in this shadow the result is a solar eclipse,

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3 years ago
A playground merry-go-round of radius R = 2.20 m has a moment of inertia I = 260 kg · m2 and is rotating at 12.0 rev/min about a
MrRa [10]

Answer:

The new angular speed of the merry-go-round is 8.31 rev/min.

Explanation:

Because the merry-go-round is rotating about a frictionless axis there’re not external torques if we consider the system merry-go-round and child. Due that we can apply conservation fo angular momentum that states initial angular momentum (Li) should be equal final angular momentum (Lf):

L_f=L_i (1)

The initial angular momentum is just the angular momentum of the merry-go-round (Lmi) that because it's a rigid body is defined as:

L_i=L_{mi}=I\omega_i (2)

with I the moment of inertia and ωi the initial angular speed of the merry-go-round

The final angular momentum is the sum of the final angular momentum of the merry-go-round plus the final angular momentum of the child (Lcf):

L_f=L_{mf}+L{cf}=I\omega_f+L{cf} (3)

The angular momentum of the child should be modeled as the angular momentum of a punctual particle moving around an axis of rotation, this is:

L{cf}=mRv_f (4)

with m the mass of the child, R the distance from the axis of rotation and vf is final tangential speed, tangential speed is:

v_f=\omega_f R (5)

(note that the angular speed is the same as the merry-go-round)

using (5) on (4), and (4) on (3):

L_f=I\omega_f+m\omega_f R^2 (6)

By (5) and (2) on (1):

I\omega_f+m\omega_f R^2=I\omega_i

Solving for ωf (12.0 rev/min = 1.26 rad/s):

\omega_f= \frac{I\omega_i}{]I+mR^2}=\frac{(260)(1.26)}{260+(24.0)(2.20)^2}

\omega_f=0.87\frac{rad}{s}=8.31 \frac{rev}{min}

8 0
3 years ago
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