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kherson [118]
3 years ago
6

Find the acceleration of a body whose velocity increases from 11ms-1 to 33ms-1 in 10 seconds

Physics
2 answers:
Anvisha [2.4K]3 years ago
8 0
Acceleration is equivalent to the rate of change of velocity.

Calculate the difference of velocity, and divide by the total time it took for the change to happen.

(33 \frac{m}{s}  - 11 \frac{m}{s} ) \div 10seconds \\  = 2 \frac{m}{ {s}^{2} }
That is the answer.
Alex777 [14]3 years ago
7 0
As we know that 
a= dell   V/t
then put values
a=   2ms/^2
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