3 years ago

If earth had no atmosphere, would a falling object ever reach terminal velocity?

1 answer:

5 0

No, because terminal velocity is when the acceleration of the Earth’s gravity is balanced by the air resistance of the atmosphere.

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How did she change the circuit?

klio [65]

Answer:

She changed a closed circuit to an open circuit

Explanation:

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3 years ago

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Which of the following is not something that the atmosphere does for us?

Masja [62]

Tha atmosphere has no effect on gravity.

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3 years ago

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2. A 2.5 meter-long wave travels at 1 m/s towards a fixed boundary. After 2 seconds, how does the wave appear?

Elan Coil [88]

Answer:

Since incident wave and its reflected part in opposite phase superimpose on each other

So correct answer will be

Option B

Explanation:

Here we know that the wave reflection is done by rigid boundary

So when wave is reflected by the boundary then its phase is reversed by 180 degree

so the reflected wave is in reverse phase from the boundary

so we can superimpose the reflected part with incident wave to dine the resultant wave

So the phenomenon is given as follow

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3 years ago

When the temperature of matter decrease , the particles do what

Rom4ik [11]

Answer:

When the temperature decreases the particals start to slow down.

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3 years ago

An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o

Viktor [21]

Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

$T=2\pi\sqrt{\dfrac{m}{k}}$

m is the mass of object

$m=\dfrac{W}{g}$

$m=\dfrac{2.45}{9.8}$

m = 0.25 kg

$k=\dfrac{4\pi^2m}{T^2}$

$k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}$

k = 24.09 N/m

k = 24.11 N/m

So, the spring constant of the spring is 24.1 N/m.

6 0

2 years ago