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Ede4ka [16]
3 years ago
12

An LC circuit consists of a 3.14 mH inductor and a 5.08 µF capacitor. (a) Find its impedance at 55.7 Hz. 563.57 Correct: Your an

swer is correct. Ω (b) Find its impedance at 11.0 kHz.
Physics
1 answer:
ANEK [815]3 years ago
4 0

Answer:

a)

z=561.7

b)

z=214.1

Explanation:

L = inductance of the Inductor = 3.14 mH = 0.00314 H

C = capacitance of the capacitor = 5.08 x 10⁻⁶ F

a)

f = frequency = 55.7 Hz

Impedance is given as

z=\frac{1}{2\pi fC} - 2\pi fL

z=\frac{1}{2(3.14) (55.7)(5.08\times 10^{-6})} - 2(3.14) (55.7)(0.00314)

z=561.7

b)

f = frequency = 11000 Hz

Impedance is given as

z= - \frac{1}{2\pi fC} + 2\pi fL

z= - \frac{1}{2(3.14) (11000)(5.08\times 10^{-6})} + 2(3.14) (11000)(0.00314)

z=214.1

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