Answer:
temperature and mass
Explanation:
- The higher the temperature of a given quantity of a substance, more is its thermal energy.
- If a substance contains more mass, this also implies that the object has more particles in it . hence, it has high thermal energy.
<em><u>A</u></em><em><u>d</u></em><em><u>d</u></em><em><u>i</u></em><em><u>t</u></em><em><u>i</u></em><em><u>o</u></em><em><u>n</u></em><em><u>a</u></em><em><u>l</u></em><em><u> </u></em><em><u>I</u></em><em><u>n</u></em><em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u>m</u></em><em><u>a</u></em><em><u>t</u></em><em><u>i</u></em><em><u>o</u></em><em><u>n</u></em><em><u> </u></em>:
- Temperature is a measure of the average kinetic energy of the particles of a substance.
- The thermal energy of an object depends on three factors:
- number of molecules in the object
- temperature of the object.
- thermal energy it has.
Scientists could investigate this idea by making cathode ray tubes out of different materials to see if the ray was the same.
The first question would be A
The second would be either A or D
Answer:
0.08 w
Explanation:
AVERAGE POWER : Average power is defined as the average work per unit time. average power is denoted by P its depend on the voltage current and power factor.
the expression for the average power is given as
P=
cosΦ
We have given maximum voltage =8 volt
=
power factor =.25
resistance =25Ω
power factor =
power factor=
From here Z=100
P=
×
×cosΦ
=5.6577×0.05677×0.25
=0.08w
Answer:
44.3 m/s
Explanation:
Given that a ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally away from and below the point of release.
What is the magnitude of its velocity just before it strikes the ground ?
The parameters given are:
Height H = 100m
Since the ball is thrown from a top of a building, initial velocity U = 0
Let g = 9.8m/s^2
Using third equation of motion
V^2 = U^2 + 2gH
Substitute all the parameters into the formula
V^2 = 2 × 9.8 × 100
V^2 = 200 × 9.8
V^2 = 1960
V = 44.27 m/s
Therefore, the magnitude of its velocity just before it strikes the ground is 44.3 m/s approximately