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Sophie [7]
3 years ago
9

Write  as a fraction in simplest form.

Mathematics
2 answers:
bezimeni [28]3 years ago
7 0
0.55= 11/ 20 as a fraction simplest form 
deff fn [24]3 years ago
4 0
55/100 but then you reduce it and it becomes 11/20
hope that helps!
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The Ruiz family is exchanging euros for US dollars. The exchange rate is 1 euro equals 1.35261 USD. Since the Ruiz family knows
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1 euro = 1.35261 USD

The Ruiz family will be able to exchange their euros for US dollar using the rate of $1.35 per 1 euro.


4 0
3 years ago
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You are working in a primary care office. Flu season is starting. For the sake of public health, it is critical to diagnose peop
Aleksandr-060686 [28]

Answer:

E. 0.11

Step-by-step explanation:

We have these following probabilities:

A 10% probability that a person has the flu.

A 90% probability that a person does not have the flu, just a cold.

If a person has the flu, a 99% probability of having a runny nose.

If a person just has a cold, a 90% probability of having a runny nose.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem, we have that:

What is the probability that a person has the flu, given that she has a runny nose?

P(B) is the probability that a person has the flu. So P(B) = 0.1.

P(A/B) is the probability that a person has a runny nose, given that she has the flu. So P(A/B) = 0.99.

P(A) is the probability that a person has a runny nose. It is 0.99 of 0.1 and 0.90 of 0.90. So

P(A) = 0.99*0.1 + 0.9*0.9 = 0.909

What is the probability that this person has the flu?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.1*0.99}{0.909} = 0.1089 = 0.11

The correct answer is:

E. 0.11

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Step-by-step explanation:

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I need help trying to find the answer to -4(x-1)=-3x+31
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5 0
3 years ago
Before calculators were around, why was it's advantageous to use logarithms to calculate roots
neonofarm [45]
Because logarithms were a lot less time-consuming than other methods of finding roots. They were also more accurate in the sense that it was harder to make a mistake.
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3 years ago
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