Which is greater , 0.9 or 1.4

Mathematics

1 answer:

nexus9112 [7]3 years ago

5 0

1.4 is greater than 0.9 by 0.5
1.4 is one whole, four tenths
0.5 is five tenths

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I need ur smart brain power!!!!!

Andrej [43]

Answer:

y = -2x -3

Step-by-step explanation:

I love slope-intercept form! lol

y =mx +b

so we have 2 points given: (-1,5) and (4,-5)

to find the SLOPE of the slope-intercept form, we need to subtract and divide

(-5-5)/(4+1)

-10/5= -2 which is our slope

now! lets translate this info into point slope form. y - y1 = m (x - x1)

(-1,5) and we kno the slope is -2.

y - 5 = -2 (x - (-1))

y-5 = -2(x + 1)

y-5 = -2x -2

add five

y = -2x -3 we are back to slope intercept form! YAY!

3 0

3 years ago

Which is the ordered pair for the point on the x-axis

mariarad [96]

The ordered pair for the point on the x-axis that is on the line parallel to the given line and through the given point (-6, 10) is:

$\boxed{(6,0)}$

<h2>Explanation:</h2>

The complete question includes a graph. I have found it on the internet and has been attached below. So:

<em>To find an </em><em>ordered pair</em><em> for the point on the x-axis that is on the line parallel to the given line and through the given point (-6, 10)</em>

With two points we can get the slope of a line, so for the given linewe have the following slope (m):

$P_{1}(-8,6) \\ \\ P_{2}(4,-4) \\ \\ \\ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ m=\frac{-4-6}{4-(-8)} \\ \\ m=-\frac{10}{12}=-\frac{5}{6}$

Since the line we are looking for is parallel to the given line, then the slope of our unknown line (let's call it $m_{x}$ ) equals the slope of the given line. In other words:

$m_{x}=m=-\frac{5}{6}$

The point slope form of the equation of a line is:

$y-y_{0}=m(x-x_{0}) \\ \\ Where: \\ \\ P_{0}(x_{0},y_{0}) \ is \ a \ point \ on \ the \ line \\ \\ Here: \\ \\ P_{0}(-6,10) \\ \\ \\ Accordingly: \\ \\ y-10=-\frac{5}{6}(x-(-6)) \\ \\ y-10=-\frac{5}{6}(x+6)$

Finally, to find the ordered pair on the x-axis let's set $y=0$ then:

$y-10=-\frac{5}{6}(x+6) \\ \\ 0-10=-\frac{5}{6}(x+6) \\ \\ Isolating \ x: \\ \\ -\frac{5}{6}x-5=-10 \\ \\ \\ Add \ 5 \ to \ both \ sides: \\ \\ -\frac{5}{6}x-5+5=-10+5 \\ \\ -\frac{5}{6}x=-5 \\ \\ \\ Multiply \ by \ -\frac{6}{5} \ both \ sides: \\ \\ (-\frac{6}{5})(-\frac{5}{6}x)=(-5)(-\frac{6}{5}) \\ \\ \boxed{x=6}$