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3 years ago

Please answer correctly!!! Will mark brainliest !!!

Mathematics

1 answer:

Mama L [17]3 years ago

4 0

Answer:

7^15/3^30

Step-by-step explanation:

Note how the exponents are negative. To make them positive, flip the numerator and the denominator (keep everything else the same). The equation becomes (7^3/3^6)^5.

Now, multiply the 5 by each exponent. The equation becomes 7^15/3^30, which is one of the options.

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Write a problem that can be answered by solving X + 16 = 30

weqwewe [10]

Answer:

X= 14

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Jose, baulus, and George are having a disagreement over interest rates. Jose says that 6 3/4% can be expressed as 6.75%. George

otez555 [7]

Answer:

Jose and George are correct

Baulus is incorrect

Step-by-step explanation:

Given

$6\frac{3}{4}$ %

Required

Compare the above expression with

Jose: 6.75%.

George: 0.0675

Baulus: 0.0675%

<em>The expression </em> $6\frac{3}{4}$ <em>% is given as a mixed fraction;</em>

In Jose's case, he simply converted it to decimal

Converting $6\frac{3}{4}$ % to decimal;

First, we need to convert to improper fraction

$6\frac{3}{4}$ % in improper fraction is $\frac{27}{4}$ %

Then, we divide the numerator by the denominator

$\frac{27}{4}$ % = 6.75%.

Hence, Jose is correct

In George's case, he solved further by removing the % from Jose's answer.

% means divided by 100; In other words, x% means that we divide x by 100

So, 6.75% means we divide 6.75 by 100

$\frac{6.75}{100}$ = 0.0675

Hence, George is also correct

But same can't be said of Baulus;

Baulus converted $6\frac{3}{4}$ % as 0.0675%

This means that he converted $6\frac{3}{4}$ as 0.0675 then he appended it with the percentage sign (%)

Since $6\frac{3}{4}$ is not equal to 0.0675, then we can conclude that Baulus is incorrect

8 0

3 years ago

A rope is 50 meters long. It is cut into two pieces and one piece is 8 meters longer than the other. What are the two lengths?

Mashcka [7]

Answer:

21 meters and 29 meters

Step-by-step explanation:

x + (x + 8) = 50

2x + 8 = 50

2xc = 42

x = 21

x + 8 = 29

6 0

3 years ago

Consider the toss of four coins. There are 16 (i.e., 24) possible outcomesin one toss. (a)Calculate the probabilities that there

lana [24]

Answer:

See answers below

Step-by-step explanation:

If 4 coins are tossed. the total possible outcomes are;

H H H H , H H H T, H H T H, H T H H, T H H H , H H T T, H T T H, T T H H, H T H T, T H T H, T H H T , H T T T, T H T T, T T H T, T T T H and T T T T

Total outcomes = 16

1) zero head = T T T T = 1 outcome

Probability = Expected/Total outcome

Pr(zero head) = 1/16

2) one head = H T T T, T H T T, T T H T, T T T H = 4 outcomes

Probability = Expected/Total outcome

Probability = 4/16

Pr(one head) = 1/4

3) two heads = H H T T, H T T H, T T H H, H T H T, T H T H, T H H T = 6 outcomes

Probability = Expected/Total outcome

Pr(two head) = 6/16

Pr(two head) = 3/8

4) three heads = H H H T, H H T H, H T H H, T H H H = 4 outcomes

Probability = Expected/Total outcome

Pr(three heads) = 4/16

Pr(two head) = 1/4

5) four heads appearing on the four coins = H H H H = 1 outcome

Pr(four heads) = 1/16

6 0

3 years ago

I need help ASAP! Can anyone please check my work?

STALIN [3.7K]

A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

8 0

3 years ago