Answer:
The Supersmack gum has a volume of
cm^3 or
cm^3. So, Supersmack's cylindrical bubble gum has more actual gum than the Megapop gumball
Step-by-step explanation:
Assuming that the radius of the Megapop gumball is 1.5 (the same diameter as Supersmack)
The volume of the cylinder's equation can be written as

This simplifies to
cm^3 or
cm^3
The volume of the gumball's equation can be written as

This simplifies to
cm^3 or
cm^3
The Supersmack gum has a volume of
cm^3 or
cm^3. So, Supersmack's cylindrical bubble gum has more actual gum than the Megapop gumball
(D) hope this helps kxjdndldjdkwpwnx
' 4 ' itself is a fine counterexample.
4 is divisible by 4 but not by 8 .
Any odd-multiple of 4 is another counterexample.
In other words, only even-multiples of 4 are divisible by 8 .
Assuming that the corner of the fence has right angle, the the area that the dog wandered will be given by:
A=θ/360πr²
Where:
θ=360-90=270°
r=49 ft
hence the area will be:
A=270/360×π×49²
A=5657.23 ft²
Thus the dog will wander in the area of 5657.23 ft²
Answer:
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