121+b^2=12.1^2 What is the value of b^2?

1 answer:

5 0

$121 + b^2 = 12.1^2$
Square 12.1, and subtract 121 from both sides.
$b^2 = 146.41 - 121$
Complete the subtraction on the right side.
$b^2 = 25.41$
This is the solution.

$b^2 = 25.41$

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