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DIA [1.3K]
4 years ago
5

121+b^2=12.1^2 What is the value of b^2?

Mathematics
1 answer:
luda_lava [24]4 years ago
5 0
121 + b^2 = 12.1^2
Square 12.1, and subtract 121 from both sides.
b^2 = 146.41 - 121
Complete the subtraction on the right side. 
b^2 = 25.41
This is the solution. 

b^2 = 25.41
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