<span>∫[(secx)−1<span>]<span>(1/2)</span></span>dx?</span> or <span>∫[sec(x−1)<span>]<span>(1/2)</span></span>dx hope it works</span>
Answer:
5/9
Step-by-step explanation:
Set h to 640 and solve for t:
640 = -490t^2 + 1120t
Subtract 640 from both sides:
-490t^2 + 1120t - 640 = 0
The formula to solve a quadratic equation is:
x = -b -/+ sqrtroot (b^2-4ac)/(2a) where a = -490, b = 1120 and c = -640
Solve:
x = -1120 -/+ sqrtroot (1120^2-4(-490)(-640) )/ 2(-490)
x = 8/7 = 1.1428 = 1.14
Time was 1.14 seconds
Answer:
sorry I didn't have my phone on me, look at the photo it's the answer btw
Step-by-step explanation: