Question

Heelppppppppp!!!!! Please?!

Answer 1

To calculate the area shaded green, we first calculate the sum of areas S=A1+A2+A3.   The green area is the area of circle A less the sum of white areas S.

Also, note that the

area of an equilateral triangle with side s

=(sqrt(3)*s)*s/2

=sqrt(3)*s^2/2.

Proceeding,

A1

=sqrt(3)s^2/2

=sqrt(3)7^2/2

=49sqrt(3)/2

A2

=60/360 of the area of the circle

=60/360*(pi r^2)

=1/6*(pi*7^2)

=49pi/6

A3=A1

=49sqrt(3)/2

S=A1+A2+A3

=49sqrt(3)/2+49pi/6+49sqrt(3)/2

=49sqrt(3)+49pi/6

=49(sqrt(3)+pi/6)

Area shaded green

= pi r^2 - S

=pi 7^2 - S

=49pi - 49(sqrt(3)+pi/6)

=49(5pi/6-sqrt(3))

Answer 2

To calculate h evaluate inside the square root before taking the square root

h = √(7² - 3.5²) = √(49 - 12.25) = √36.75 = 6.06 ( to 2 dec. places)